Christopher uses monochromatic light and shines it on a material with index of refraction 1.5, surrounded by water on one side and air on the other side. If the light has wavelength 534 nm within the film, what is the film thickness in nanometers for which maximum constructive interference between the incident beam and the reflected beam occurs? Please give your answer as a whole number.
Christopher uses monochromatic light and shines it on a material with index of refraction 1.5, surrounded by water on one side and air on the other side. If the light has wavelength 534 nm within the film, what is the film thickness in nanometers for which maximum constructive interference between the incident beam and the reflected beam occurs? Please give your answer as a whole number.
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Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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![**Problem Statement:**
Christopher uses monochromatic light and shines it on a material with an index of refraction 1.5, surrounded by water on one side and air on the other side. If the light has a wavelength of 534 nm within the film, what is the film thickness in nanometers for which maximum constructive interference between the incident beam and the reflected beam occurs? Please give your answer as a whole number.
**Solution Explanation:**
To determine the film thickness \( t \) for maximum constructive interference, we must use the formula:
\[ 2 t = m \lambda_n \]
where:
- \( m \) is the order of interference (m = 0, 1, 2,... for constructive interference)
- \( \lambda_n \) is the wavelength of light in the film.
Given:
- \( \lambda_n = 534 \) nm
- The index of refraction \( n = 1.5 \)
For the first order (constructive interference, m = 1):
\[ 2t = 1 \times 534\ \text{nm} \]
\[ t = \frac{534}{2}\ \text{nm} \]
\[ t = 267\ \text{nm} \]
So, the film thickness for maximum constructive interference is **267 nanometers**.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcb865a02-7408-4eb8-b9f3-2c56928a70f5%2Fba8b4d65-0b8e-4fd0-b5e5-794566cdb8aa%2Fs8ggkbv_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
Christopher uses monochromatic light and shines it on a material with an index of refraction 1.5, surrounded by water on one side and air on the other side. If the light has a wavelength of 534 nm within the film, what is the film thickness in nanometers for which maximum constructive interference between the incident beam and the reflected beam occurs? Please give your answer as a whole number.
**Solution Explanation:**
To determine the film thickness \( t \) for maximum constructive interference, we must use the formula:
\[ 2 t = m \lambda_n \]
where:
- \( m \) is the order of interference (m = 0, 1, 2,... for constructive interference)
- \( \lambda_n \) is the wavelength of light in the film.
Given:
- \( \lambda_n = 534 \) nm
- The index of refraction \( n = 1.5 \)
For the first order (constructive interference, m = 1):
\[ 2t = 1 \times 534\ \text{nm} \]
\[ t = \frac{534}{2}\ \text{nm} \]
\[ t = 267\ \text{nm} \]
So, the film thickness for maximum constructive interference is **267 nanometers**.
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