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C,H,,O(s) + 6 0,(g) → 6 CO,(g) + 6 H,O() AH° = -2803.02 kJ (3) H (8)0% + MO'H %3D (8)0) (3)O + (s)Ɔ %3D AH° = -285.8 kJ using the following three equations: AH° = -285.8 kJ Calculate AH for the reaction: (3) 9 + ($)Ɔ 9 (s)°O"H?Ɔ *see back!

C,H,,O(s) + 6 0,(g) → 6 CO,(g) + 6 H,O() AH° = -2803.02 kJ (3) H (8)0% + MO'H %3D (8)0) (3)O + (s)Ɔ %3D AH° = -285.8 kJ using the following three equations: AH° = -285.8 kJ Calculate AH for the reaction: (3) 9 + ($)Ɔ 9 (s)°O"H?Ɔ *see back!

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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See image below. The answer I got is 

-626.58 kJ...is that correct?

C,H,,O(s) + 6 0,(g) → 6 CO,(g) + 6 H,O() AH° = -2803.02 kJ (3) H (8)0% + MO'H %3D (8)0) (3)O + (s)Ɔ %3D AH° = -285.8 kJ using the following three equations: AH° = -285.8 kJ Calculate AH for the reaction: (3) 9 + ($)Ɔ 9 (s)°O"H?Ɔ *see back!
Transcribed Image Text:C,H,,O(s) + 6 0,(g) → 6 CO,(g) + 6 H,O() AH° = -2803.02 kJ (3) H (8)0% + MO'H %3D (8)0) (3)O + (s)Ɔ %3D AH° = -285.8 kJ using the following three equations: AH° = -285.8 kJ Calculate AH for the reaction: (3) 9 + ($)Ɔ 9 (s)°O"H?Ɔ *see back!
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