Why is the last answer choice correct? **Question:**Choose the equation that correctly represents the standard enthalpy of formation for CO if the standard enthalpy of formation for CO is -110.5 kJ/mol.**Options:**1. \( \text{C}_{\text{graphite}}(s) + \text{CO}_2(g) \rightarrow 2 \, \text{CO}(g) \) \( \Delta H^\circ = -110.5 \, \text{kJ} \)2. **You Answered:** \( 2 \, \text{C}_{\text{graphite}}(s) + \text{O}_2(g) \rightarrow 2 \, \text{CO}(g) \) \( \Delta H^\circ = -110.5 \, \text{kJ} \)3. \( \text{CO}(g) \rightarrow \text{C}_{\text{graphite}}(s) + \text{O}_2(g) \) \( \Delta H^\circ = -110.5 \, \text{kJ} \)4. \( \text{C}_{\text{graphite}}(s) + \text{O}(g) \rightarrow 2 \, \text{CO}(g) \) \( \Delta H^\circ = -110.5 \, \text{kJ} \)5. **Correct Answer:** \( \text{C}_{\text{graphite}}(s) + \frac{1}{2} \, \text{O}_2(g) \rightarrow \text{CO}(g) \) \( \Delta H^\circ = -110.5 \, \text{kJ} \)**Explanation:**The correct answer represents the standard formation reaction of carbon monoxide (CO) from its elements in their standard states, that is, graphite and dioxygen gas. In a formation reaction, one mole of the compound is produced from its elements, so the correct equation is:\[ \text{C}_{\text{graphite}}(s) + \frac{1}{2} \text{O}_2(g) \rightarrow \text{CO}(g) \]and the enthalpy change (\( \Delta H^\circ \)) is given as -110.5 kJ/mol for this process.

Choose the equation that correctly represents the standard enthalpy of formation for CO if the standard enthalpy of formation for CO is -110.5 kJ/mol. O Cgraphite(s) + CO2(g) → 2 CO(g) AH° = -110.5 kJ You Answered 2 Cgraphite(s) + O2(g) –→ 2 CO(g) AH° = -110.5 kJ CO(g) → Cgraphite(S) + O2(g) AH° = -110.5 kJ O Cgraphite(s) + O(g) → 2 CO(g) A H° = -110.5 kJ Correct Answer O Cgraphite(s) + O2(g) → 2 CO(g) AH° = -110.5 kJ

Choose the equation that correctly represents the standard enthalpy of formation for CO if the standard enthalpy of formation for CO is -110.5 kJ/mol. O Cgraphite(s) + CO2(g) → 2 CO(g) AH° = -110.5 kJ You Answered 2 Cgraphite(s) + O2(g) –→ 2 CO(g) AH° = -110.5 kJ CO(g) → Cgraphite(S) + O2(g) AH° = -110.5 kJ O Cgraphite(s) + O(g) → 2 CO(g) A H° = -110.5 kJ Correct Answer O Cgraphite(s) + O2(g) → 2 CO(g) AH° = -110.5 kJ

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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