Chlorine can be prepared in the laboratory by the reaction of manganese dioxide with hydrochloric acid, HCl(aq), as described by the chemical equation MnO, (s) + 4 HCl(aq) → MnCl, (aq) + 2 H, O(1) + Cl, (g) How much Mno, (s) should be added to excess HCl(aq) to obtain 285 mL Cl, (g) at 25 °C and 705 Torr? mass of MnO,: g
Chlorine can be prepared in the laboratory by the reaction of manganese dioxide with hydrochloric acid, HCl(aq), as described by the chemical equation MnO, (s) + 4 HCl(aq) → MnCl, (aq) + 2 H, O(1) + Cl, (g) How much Mno, (s) should be added to excess HCl(aq) to obtain 285 mL Cl, (g) at 25 °C and 705 Torr? mass of MnO,: g
Chemistry
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Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Chlorine Production in the Laboratory**
Chlorine can be prepared in the laboratory by the reaction of manganese dioxide with hydrochloric acid, \( \text{HCl(aq)} \), as described by the chemical equation:
\[
\text{MnO}_2(s) + 4 \text{HCl(aq)} \longrightarrow \text{MnCl}_2(aq) + 2 \text{H}_2\text{O(l)} + \text{Cl}_2(g)
\]
**Question:**
How much \( \text{MnO}_2(s) \) should be added to excess \( \text{HCl(aq)} \) to obtain 285 mL \( \text{Cl}_2(g) \) at 25 °C and 705 Torr?
**Calculation:**
*Enter the mass of \( \text{MnO}_2 \):* \_\_\_\_ g](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc6ae9165-8c64-40e9-9a68-65bc31ca98b7%2F3cb260e0-1bdf-49e2-b9f4-71c7e281da7f%2Fys3ncve_processed.png&w=3840&q=75)
Transcribed Image Text:**Chlorine Production in the Laboratory**
Chlorine can be prepared in the laboratory by the reaction of manganese dioxide with hydrochloric acid, \( \text{HCl(aq)} \), as described by the chemical equation:
\[
\text{MnO}_2(s) + 4 \text{HCl(aq)} \longrightarrow \text{MnCl}_2(aq) + 2 \text{H}_2\text{O(l)} + \text{Cl}_2(g)
\]
**Question:**
How much \( \text{MnO}_2(s) \) should be added to excess \( \text{HCl(aq)} \) to obtain 285 mL \( \text{Cl}_2(g) \) at 25 °C and 705 Torr?
**Calculation:**
*Enter the mass of \( \text{MnO}_2 \):* \_\_\_\_ g
Expert Solution
Step 1
Given
Temperature = 25 oC = (273+25)K = 298 K
Pressure = 705 torr = 705/760 = 0.927 atm
Volume = 285 ml = 0.285 L
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