Children playing in a playground on the flat roof of a city school lose their ball to the parking lot below. One of the teachers kicks the ball back up to the children as shown in the figure below. The playground is 5.40 m above the parking lot, and the school building's vertical wall is h = 6.90 m high, forming a 1.50 m high railing around the playground. The ball is launched at an angle of 0 53.0° above the horizontal at a point d = 24.0 m from the base of the building wall. The ball takes 2.20 s to reach a poln vertically above the wall. (Due to the nature of this problem, do not use rounded intermediate values in your calculations-including answers submitted in WebAssign.) (a) Find the speed (in m/s) at which the ball was launched. m/s (b) Find the vertical distance (in m) by which the ball clears the wall. m (c) Find the horizontal distance (in m) from the wall to the point on the roof where the ball lands. m (d) What If? If the teacher always launches the ball with the speed found in part (a), what is the minimum angle (in degrees above the horizontal) at which he can launch the ball and still clear the playground railing? (Hint: You may need to use the trigonometric identity sec²(0) = 1 + tan²(0).) above the horizontal

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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4.
DETAILS
(a) Find the speed (in m/s) at which the ball was launched.
m/s
Children playing in a playground on the flat roof of a city school lose their ball to the parking lot below. One of the teachers kicks the ball back up to the children as shown in
the figure below. The playground is 5.40 m above the parking lot, and the school building's vertical wall is h = 6.90 m high, forming a 1.50 m high railing around the
playground. The ball is launched at an angle of 0 = 53.0° above the horizontal at a point d = 24.0 m from the base of the building wall. The ball takes 2.20 s to reach a point
vertically above the wall. (Due to the nature of this problem, do not use rounded intermediate values in your calculations-including answers submitted in WebAssign.)
(b) Find the vertical distance (in m) by which the ball clears the wall.
hs
m
Ⓡ
(c) Find the horizontal distance (in m) from the wall to the point on the roof where the ball lands.
m
MY NOTES
ASK YOUR TEACHER
(d) What If? If the teacher always launches the ball with the speed found in part (a), what is the minimum angle degrees above the horizontal) at which he can launch
the ball and still clear the playground railing? (Hint: You may need to use the trigonometric identity sec² (0) = 1 + tan²(0).)
above the horizontal

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Given:-

The height of the playground from the parking is h_p= 5.40 m

The height of the building is h = 6.90 m

The height of the railing around the playground is y = 1.50 m

The lunch angle of the ball is $θ = 53 °$

The distance between the lunch point and the base of the wall is d = 24 m.

The ball takes 2.20 sec to reach the point vertically above the wall.

Find:-

a) The speed at which the ball launched?

b) The vertical distance of the ball by which it clears the wall?

c) The Horizontal distance between the wall and the point of land on the playground?

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