Answered: Children are playing on top of a hill.…

Name: Children are playing on top of a hill. A kid pushes a sled weighing 26
Uploaded: 2024-03-20T06:56:46.000Z
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Description: Children are playing on top of a hill. A kid pushes a sled weighing 26.2kg down it on a 40 degree incline. Friction is negligible. How fast is the sled going after sliding for 121 meters? What is the acceleration?

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Children are playing on top of a hill. A kid pushes a sled weighing 26.2kg down it on a 40 degree incline. Friction is negligible. How fast is the sled going after sliding for 121 meters? What is the acceleration?

Expert Solution

Step 1

Given data

*The sled weight is w = 26.2 kg

*The angle is $θ = 40^{0}$

*The distance travelled by the sled is s = 121 m

Step 2

The expression for the speed of the sled is given by the conservation of energy as,

$\begin{array}{rcl} U_{k} & = & U_{p} \\ \frac{1}{2} m v^{2} & = & m g h \\ v & = & \sqrt{2 g h} \end{array}$

*Here U_k is the kinetic energy, U_p is the potential energy and g is the acceleration due to the gravity

Substitute values in the above expression as,

$\begin{array}{rcl} v & = & \sqrt{2 \times (9.8 m / s^{2}) (121 m)} \\ = & 48.70 m / s \end{array}$

Thus the speed of the sled is v = 48.70 m/s

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