The data show the chest size and weight of several bears. Find the regression equation, letting chest size be theindependent (x) variable. Then find the best predicted weight of a bear with a chest size of 48 inches. Is the resultclose to the actual weight of 428 pounds? Use a significance level of 0.05.atChest size (inches)Weight (pounds)Click the icon to view the critical values of the Pearson correlation coefficient rView an example49 42 D36 56 50 39296 570 501 353 487 385What is the regression equation?=+x (Round to one decimal place as needed.)H CGet more help."'10√✔(0,0)Clear allMoreX67°F SunnyIncorrect: 0Activate WindowsCheck answer Go to Settings to activateP4

The regression equation is given by, ŷ = a + bx ... (1) Where,…

Answered: Chest size (inches) 49 42 D 385 Weight…

A First Course in Probability (10th Edition)

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Chapter1: Combinatorial Analysis

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Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Research was conducted on the amount of training for 5K race and the time a contestant took to run the race. The researcher recorded the number of miles a contestant ran during the last month of training and the time it took the contestant to complete the 5K. The results are below. Miles Trained 65 78 90 91 104 112 Time (Minutes) 23 26 34 39 42 50 (a) Give the correlation coefficient. Round to one decimal place. (b) Use technology to write the regression equation that predicts the time it takes a contestant to complete the race by using the miles trained as the explanatory variable. Complete the missing parts of the equation below, rounding values to one decimal place. ý (c) Interpret the y-intercept in the context of this scenario. O Each additional mile of training reduces the time needed to complete the 5K by 0.6 minutes. A contestant who has not trained at all in the last month can expect to complete the 5K in 0.6 minutes. X O A contestant who has not trained at all in the last…
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Using your favorite statistics software package, you generate a scatter plot with a regression equation and correlation coefficient. The regression equation is reported asy=20.41x+15.59y=20.41x+15.59and the r=0.272r=0.272.What proportion of the variation in y can be explained by the variation in the values of x?r² = %Report answer as a percentage accurate to one decimal place.
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Using your favorite statistics software package, you generate a scatter plot with a regression equation and correlation coefficient. The regression equation is reported asy=98.15x+95.04y=98.15x+95.04and the r=0.73r=0.73.What proportion of the variation in y can be explained by the variation in the values of x?r² = %Report answer as a percentage accurate to one decimal place.
You generate a scatter plot using Excel. You then have Excel plot the trend line and report the equation and the ² value. The regression equation is reported as y = 49.18x + 40.52 and the r² = 0.5041. What is the correlation coefficient for this data set? r =
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M Wed Feb 15 Measles and Mumps The data show the number of cases of measles and mumps for a recent 5-year period. Measles Cases Mumps Cases 48 150 1797 475 70 60 203 1954 2575 370 Send data to Excel www-awu.connectmath.com The correlation coefficient for the data is r=-0.911 and a= 0.05. Should regression analysis be done? O The regression analysis should not be done. O The regression analysis should be done. Find the equation of the regression line. Round the coefficients to at least three decimal places. y' = a + bx a = b = Given a year with 185 cases of measles, predict the expected number of cases of mumps for that year. Round your answer to at least one decimal place. The number of cases of mumps for that year is 47% Submit Assignment 2023 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Cent 0
Direction: Answer the problem below. Show your solution. Mr. David runs to keep himself physically fit. He wants to know if there is a relationship between the time elapsed and the kilometers he ran. Kilometers ran Time (in minutes) (X) (Y) 1 10 90 2 10 60 3 16 150 4 16 90 5 21 160 21 180 a. Calculate the Pearson correlation coefficient and regression line based on the data below, b. Draw a scatter plot. Activate Windows N Go to PC settings to activate Windows.
Using your favorite statistics software package, you generate a scatter plot with a regression equation and correlation coefficient. The regression equation is reported asy=43.25x+19.44y=43.25x+19.44and the r=0.98r=0.98.What proportion of the variation in y can be explained by the variation in the values of x?r² = %
Using your favorite statistics software package, you generate a scatter plot with a regression equation and correlation coefficient. The regression equation is reported as y = 55.52x + 67.35 and the r = 0.65. What percentage of the variation in y can be explained by the variation in the values of x? r2 = % (Report exact answer, and do not enter the % sign) Submit Question Drive 8:31 ヘ回の 3/6/2 brPo 近

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Chest size (inches) 49 42 D 385 Weight (pounds) Click the icon to view the critical values of the Pearson correlation coefficient r 36 56 50 39 296 570 501 353 487 What is the regression equation? ŷ=+x (Round to one decimal place as needed.) ...