**Empirical and Molecular Formula Calculation** A compound is found to contain: - 18.28% phosphorus - 18.93% sulfur - 62.78% chlorine by mass. *To answer the question, enter the elements in the order presented above.* **QUESTION 1:** - The empirical formula for this compound is: [Input Box] **QUESTION 2:** - The molar mass for this compound is 169.4 g/mol. - The molecular formula for this compound is: [Input Box] **Additional Notes:** - You have 9 more group attempts remaining. - Use the "Submit Answer" option to check your response. - You may also choose "Retry Entire Group" if needed. For any technical issues, please contact Cengage Technical Support.
**Empirical and Molecular Formula Calculation** A compound is found to contain: - 18.28% phosphorus - 18.93% sulfur - 62.78% chlorine by mass. *To answer the question, enter the elements in the order presented above.* **QUESTION 1:** - The empirical formula for this compound is: [Input Box] **QUESTION 2:** - The molar mass for this compound is 169.4 g/mol. - The molecular formula for this compound is: [Input Box] **Additional Notes:** - You have 9 more group attempts remaining. - Use the "Submit Answer" option to check your response. - You may also choose "Retry Entire Group" if needed. For any technical issues, please contact Cengage Technical Support.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Step 1
Given:
Percent of phosphorous = 18.28 %
Percent of sulfur = 18.93 %
Percent of chlorine = 62.78 %
molar mass of the compound = 169.4 g/mol
molar mass of phosphorous = 30.97 g/mol
molar mass of sulfur = 32.065 g/mol
molar mass of chlorine = 35.45 g/mol
let mass of compound be 100g.
100 g of compound contains 18.28 g of phosphorous, 18.93 g of sulfur and 62.78 g of chlorine.
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