**Problem Statement:** Enter your answer in the provided box. What is the pH of 0.80 M NaF? pH = [______] --- **Explanation:** The task is to calculate the pH of a 0.80 M solution of sodium fluoride (NaF). To find the pH, we need to understand the dissociation of NaF in water and the resulting chemical equilibrium. Here are some steps and concepts that can be used: 1. **Dissociation of NaF:** - NaF, when dissolved in water, dissociates into Na⁺ and F⁻ ions. 2. **Hydrolysis of F⁻:** - The F⁻ ion (fluoride) can react with water to form HF and OH⁻ (hydroxide ions), which makes the solution basic. - Equation: F⁻ + H₂O ⇌ HF + OH⁻ 3. **pH Calculation:** - Use the equilibrium expression to find [OH⁻], then calculate pOH. - Convert pOH to pH using the equation: pH + pOH = 14. **Note:** - Understanding the concept of weak acids and bases is important, as HF is a weak acid influencing the basic nature of the solution. - Typically, additional information such as the Ka value of HF might be needed for precise calculations.
**Problem Statement:** Enter your answer in the provided box. What is the pH of 0.80 M NaF? pH = [______] --- **Explanation:** The task is to calculate the pH of a 0.80 M solution of sodium fluoride (NaF). To find the pH, we need to understand the dissociation of NaF in water and the resulting chemical equilibrium. Here are some steps and concepts that can be used: 1. **Dissociation of NaF:** - NaF, when dissolved in water, dissociates into Na⁺ and F⁻ ions. 2. **Hydrolysis of F⁻:** - The F⁻ ion (fluoride) can react with water to form HF and OH⁻ (hydroxide ions), which makes the solution basic. - Equation: F⁻ + H₂O ⇌ HF + OH⁻ 3. **pH Calculation:** - Use the equilibrium expression to find [OH⁻], then calculate pOH. - Convert pOH to pH using the equation: pH + pOH = 14. **Note:** - Understanding the concept of weak acids and bases is important, as HF is a weak acid influencing the basic nature of the solution. - Typically, additional information such as the Ka value of HF might be needed for precise calculations.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
Related questions
Question
![**Problem Statement:**
Enter your answer in the provided box.
What is the pH of 0.80 M NaF?
pH = [______]
---
**Explanation:**
The task is to calculate the pH of a 0.80 M solution of sodium fluoride (NaF). To find the pH, we need to understand the dissociation of NaF in water and the resulting chemical equilibrium. Here are some steps and concepts that can be used:
1. **Dissociation of NaF:**
- NaF, when dissolved in water, dissociates into Na⁺ and F⁻ ions.
2. **Hydrolysis of F⁻:**
- The F⁻ ion (fluoride) can react with water to form HF and OH⁻ (hydroxide ions), which makes the solution basic.
- Equation: F⁻ + H₂O ⇌ HF + OH⁻
3. **pH Calculation:**
- Use the equilibrium expression to find [OH⁻], then calculate pOH.
- Convert pOH to pH using the equation: pH + pOH = 14.
**Note:**
- Understanding the concept of weak acids and bases is important, as HF is a weak acid influencing the basic nature of the solution.
- Typically, additional information such as the Ka value of HF might be needed for precise calculations.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7efc92fb-f6e6-45fd-bcd8-2c3c0a4ba455%2Fc39424bf-419a-4fcd-9859-ff27420981a3%2Fwgjtd09.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
Enter your answer in the provided box.
What is the pH of 0.80 M NaF?
pH = [______]
---
**Explanation:**
The task is to calculate the pH of a 0.80 M solution of sodium fluoride (NaF). To find the pH, we need to understand the dissociation of NaF in water and the resulting chemical equilibrium. Here are some steps and concepts that can be used:
1. **Dissociation of NaF:**
- NaF, when dissolved in water, dissociates into Na⁺ and F⁻ ions.
2. **Hydrolysis of F⁻:**
- The F⁻ ion (fluoride) can react with water to form HF and OH⁻ (hydroxide ions), which makes the solution basic.
- Equation: F⁻ + H₂O ⇌ HF + OH⁻
3. **pH Calculation:**
- Use the equilibrium expression to find [OH⁻], then calculate pOH.
- Convert pOH to pH using the equation: pH + pOH = 14.
**Note:**
- Understanding the concept of weak acids and bases is important, as HF is a weak acid influencing the basic nature of the solution.
- Typically, additional information such as the Ka value of HF might be needed for precise calculations.
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