### Balancing Chemical Equations #### Example Equation: **Is this balanced?** \[ \text{CuCl}_2 + \text{H}_2\text{S} \rightarrow \text{CuS} + 2\text{HCl} \] **Count how many you have on each side!!** --- ### Analysis: To balance a chemical equation, you need to ensure the number of each type of atom is the same on both the reactant and product sides of the equation. Let's break down the equation: #### Reactants: - CuCl₂ (Copper(II) chloride) - H₂S (Hydrogen sulfide) #### Products: - CuS (Copper sulfide) - 2HCl (Hydrochloric acid) ### Step-by-Step Balancing: 1. **Count the number of each type of atom on both sides of the equation.** - **Reactants:** - Cu: 1 - Cl: 2 - H: 2 - S: 1 - **Products:** - Cu: 1 - Cl: 2 (from 2HCl) - H: 2 (from 2HCl) - S: 1 Upon comparison, you can see that the number of each type of atom is already equivalent on both sides. ### Conclusion: Therefore, the chemical equation is balanced as written. \[ \text{CuCl}_2 + \text{H}_2\text{S} \rightarrow \text{CuS} + 2\text{HCl} \]
### Balancing Chemical Equations #### Example Equation: **Is this balanced?** \[ \text{CuCl}_2 + \text{H}_2\text{S} \rightarrow \text{CuS} + 2\text{HCl} \] **Count how many you have on each side!!** --- ### Analysis: To balance a chemical equation, you need to ensure the number of each type of atom is the same on both the reactant and product sides of the equation. Let's break down the equation: #### Reactants: - CuCl₂ (Copper(II) chloride) - H₂S (Hydrogen sulfide) #### Products: - CuS (Copper sulfide) - 2HCl (Hydrochloric acid) ### Step-by-Step Balancing: 1. **Count the number of each type of atom on both sides of the equation.** - **Reactants:** - Cu: 1 - Cl: 2 - H: 2 - S: 1 - **Products:** - Cu: 1 - Cl: 2 (from 2HCl) - H: 2 (from 2HCl) - S: 1 Upon comparison, you can see that the number of each type of atom is already equivalent on both sides. ### Conclusion: Therefore, the chemical equation is balanced as written. \[ \text{CuCl}_2 + \text{H}_2\text{S} \rightarrow \text{CuS} + 2\text{HCl} \]
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
![### Balancing Chemical Equations
#### Example Equation:
**Is this balanced?**
\[ \text{CuCl}_2 + \text{H}_2\text{S} \rightarrow \text{CuS} + 2\text{HCl} \]
**Count how many you have on each side!!**
---
### Analysis:
To balance a chemical equation, you need to ensure the number of each type of atom is the same on both the reactant and product sides of the equation. Let's break down the equation:
#### Reactants:
- CuCl₂ (Copper(II) chloride)
- H₂S (Hydrogen sulfide)
#### Products:
- CuS (Copper sulfide)
- 2HCl (Hydrochloric acid)
### Step-by-Step Balancing:
1. **Count the number of each type of atom on both sides of the equation.**
- **Reactants:**
- Cu: 1
- Cl: 2
- H: 2
- S: 1
- **Products:**
- Cu: 1
- Cl: 2 (from 2HCl)
- H: 2 (from 2HCl)
- S: 1
Upon comparison, you can see that the number of each type of atom is already equivalent on both sides.
### Conclusion:
Therefore, the chemical equation is balanced as written.
\[ \text{CuCl}_2 + \text{H}_2\text{S} \rightarrow \text{CuS} + 2\text{HCl} \]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F435802c8-3c61-476a-b8bc-f54951d3dbeb%2F9023de92-59ca-4e03-a19c-8e25abaf1463%2Fc8bb2c8_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Balancing Chemical Equations
#### Example Equation:
**Is this balanced?**
\[ \text{CuCl}_2 + \text{H}_2\text{S} \rightarrow \text{CuS} + 2\text{HCl} \]
**Count how many you have on each side!!**
---
### Analysis:
To balance a chemical equation, you need to ensure the number of each type of atom is the same on both the reactant and product sides of the equation. Let's break down the equation:
#### Reactants:
- CuCl₂ (Copper(II) chloride)
- H₂S (Hydrogen sulfide)
#### Products:
- CuS (Copper sulfide)
- 2HCl (Hydrochloric acid)
### Step-by-Step Balancing:
1. **Count the number of each type of atom on both sides of the equation.**
- **Reactants:**
- Cu: 1
- Cl: 2
- H: 2
- S: 1
- **Products:**
- Cu: 1
- Cl: 2 (from 2HCl)
- H: 2 (from 2HCl)
- S: 1
Upon comparison, you can see that the number of each type of atom is already equivalent on both sides.
### Conclusion:
Therefore, the chemical equation is balanced as written.
\[ \text{CuCl}_2 + \text{H}_2\text{S} \rightarrow \text{CuS} + 2\text{HCl} \]
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