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**Part A** Calculate the molarity of 0.700 mol of glucose in 0.100 L of a glucose solution. Express your answer with the appropriate units. \[ \text{molarity} = \text{Value} \quad \text{Units} \] [Submit] [Request Answer] **Part B** Calculate the molarity of 79.5 g of HCl in 2.00 L of an HCl solution. \[ \text{Pearson} \] --- **Note:** This exercise requires students to determine the molarity of two different solutions by using the formula for molarity: \[ M = \frac{\text{moles of solute}}{\text{liters of solution}} \] For glucose, the student must use the given moles and for HCl, they need to convert the mass of HCl to moles using its molar mass before calculating molarity.

**Part A** Calculate the molarity of 0.700 mol of glucose in 0.100 L of a glucose solution. Express your answer with the appropriate units. \[ \text{molarity} = \text{Value} \quad \text{Units} \] [Submit] [Request Answer] **Part B** Calculate the molarity of 79.5 g of HCl in 2.00 L of an HCl solution. \[ \text{Pearson} \] --- **Note:** This exercise requires students to determine the molarity of two different solutions by using the formula for molarity: \[ M = \frac{\text{moles of solute}}{\text{liters of solution}} \] For glucose, the student must use the given moles and for HCl, they need to convert the mass of HCl to moles using its molar mass before calculating molarity.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Part A** Calculate the molarity of 0.700 mol of glucose in 0.100 L of a glucose solution. Express your answer with the appropriate units. \[ \text{molarity} = \text{Value} \quad \text{Units} \] [Submit] [Request Answer] **Part B** Calculate the molarity of 79.5 g of HCl in 2.00 L of an HCl solution. \[ \text{Pearson} \] --- **Note:** This exercise requires students to determine the molarity of two different solutions by using the formula for molarity: \[ M = \frac{\text{moles of solute}}{\text{liters of solution}} \] For glucose, the student must use the given moles and for HCl, they need to convert the mass of HCl to moles using its molar mass before calculating molarity.
Transcribed Image Text:**Part A** Calculate the molarity of 0.700 mol of glucose in 0.100 L of a glucose solution. Express your answer with the appropriate units. \[ \text{molarity} = \text{Value} \quad \text{Units} \] [Submit] [Request Answer] **Part B** Calculate the molarity of 79.5 g of HCl in 2.00 L of an HCl solution. \[ \text{Pearson} \] --- **Note:** This exercise requires students to determine the molarity of two different solutions by using the formula for molarity: \[ M = \frac{\text{moles of solute}}{\text{liters of solution}} \] For glucose, the student must use the given moles and for HCl, they need to convert the mass of HCl to moles using its molar mass before calculating molarity.
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Molarity of a solution is defined as the no of moles of solute in one liter of solution and it has the following formula.

MolarityM=no of moles of solutevolume of solution in liters

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