**Transcription for Educational Website** **Question 15 of 20:** Which structures represent 2-methylbutane (C₅H₁₂)? **List of Structure Options:** 1. Option 1: - Structure: CH₃-CH₂-CH(CH₃)-CH₃ 2. Option 2: - Structure: CH₃-CH(CH₃)-CH₂-CH₃ 3. Option 3: - Structure: CH₃ | CH₃-CH-CH₂ | CH₃ 4. Option 4: - Structure: CH₃-CH₂-CH₂-CH₂-CH₃ **Explanation of Structures:** - **Option 1** displays a carbon chain with a methyl group attached to the second carbon atom, accurately representing the structure of 2-methylbutane. - **Option 2** and **Option 3** have different branching patterns and do not correspond to 2-methylbutane. - **Option 4** is a straight chain of five carbon atoms, representing pentane, not 2-methylbutane. In the context of organic chemistry, identifying the correct structure of 2-methylbutane involves recognizing the branching where a methyl group (CH₃) is attached to the second carbon of the main carbon chain, consistent with option 1.

Transcription for Educational Website Question 15 of 20: Which structures represent 2-methylbutane (C₅H₁₂)? List of Structure Options: 1. Option 1: - Structure: CH₃-CH₂-CH(CH₃)-CH₃ 2. Option 2: - Structure: CH₃-CH(CH₃)-CH₂-CH₃ 3. Option 3: - Structure: CH₃ | CH₃-CH-CH₂ | CH₃ 4. Option 4: - Structure: CH₃-CH₂-CH₂-CH₂-CH₃ Explanation of Structures: - Option 1 displays a carbon chain with a methyl group attached to the second carbon atom, accurately representing the structure of 2-methylbutane. - Option 2 and Option 3 have different branching patterns and do not correspond to 2-methylbutane. - Option 4 is a straight chain of five carbon atoms, representing pentane, not 2-methylbutane. In the context of organic chemistry, identifying the correct structure of 2-methylbutane involves recognizing the branching where a methyl group (CH₃) is attached to the second carbon of the main carbon chain, consistent with option 1.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

Name the family to which each organic compound belongs. The first answer has been filled in for you. compound CH₂ || CH₂-C-0-C- CH₂ O || CH₂ || CH–C—NH, CH, OH I | CH₂-CH-C || || CH,—C–NH CH, X family ester 0
Nome The followoing organic Compand CH3 CH2 CH2-C(CH3)(OH)= CH3
Draw all possible skeletons for a 7-C compound with(a) A 6-C chain and 1 double bond(b) A 5-C chain and 1 double bond(c) A 5-C ring and no double bonds.Add the correct number of hydrogens to each of the skele-tons
5) Draw a different constitutional isomer of heptane (C₂H₁6) that contains a quaternary (4°) carbon. Then draw at least 3 other constitutional isomers.
Three structural isomers have the formula C_{5}*H_{12} Draw and name the isomers using IUPAC names. Use a hyphen (-) where necessary, not an en-dash ) Draw the isomer with 5 carbon atoms in main chain.
Following is the formula of a simple sugar. Which of the following functional groups is NOT in such a compound? O || OH H OH OH H | H-C-C-C-C-C-C-OH | | | H 1 1 OH H HH carbobyl (C=O) group O hydroxyl (-OH) group O aldehyde (-CHO) group O thiol (-SH) group hp
I cannot figure this one out!!!
A 4 T X+ W Chapter... For each of the hydrocarbon molecules shown below, write the IUPAC name. (a) (b) CH₂ (c) 3-methylhexane terra H₂C-G 3-ethyl-1-methyloctane C C CH₂ CH₂ -CH₂ X -CH₂ webassign.n C MacBook
Name the following branched-chain alkane: H,C CH2. CH2-CH3 H;C H CH; CH,-CH3
Draw and name the seven constitutional isomers (i.e., all contain a ring of some size) for cycloalkane, C,H12.
I. Isomers Requirement 1: Draw the structures of 1-bromobutane and 1-bromopropane. Then, write the molecular formula beneath each structure. (A) Are the molecular formulas identical?_(B)_ Are these compounds isomers or different compounds?___(C)_ When we compare two compounds and they are not isomers, we are finished with their classification. They are different compounds, not isomers.