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Getting Started Elite Medical Academy Online Health Courses... 2__ Survey: Week 12 Partic... B Homepage - St. Peters...prometic 4-- Screen Reader: SnC14(a q) + 2 N a2O(a q) → Sn O2(s) + 4 Na Cl(a q) Fe(CIO3)2(aq) + Na2CrO4(aq) → FeCrO4(s) + 2 NaCIO3(aq) Screen Reader: Pb(Cl 03)4(a q)+ 4 N a Cl(aq) → PbC14(s) + 4 N a Cl 03(aq) SnC14(aq) + 2 Na2O(aq) → SnO2 (s) + 4 NaCl(aq) 3 Screen Reader: F e(CI O3)2(a q) + N a2Cr 04(a q) → F e Cr 04 (s) + 2 Na Cl 03(a q) 3 Pb(ClO3)2(aq) + 2 NaCl(aq) → PbCl2(s) + 2 NaClO3(aq) _2_- Screen Reader: Pb(Cl 03)2(a q)+ 2 N a Cl(aq) → PbCl2(s) + 2N a CI O3(aq) 3 Pb(ClO3)4(aq) + 4 Na3N(aq) → Pb3N4(s) + 12 NaCIO3(aq) 11 - Screen Reader: 3 Pb(CI O3)4(a q)+ 4 N a3N(a q) → Pb3N4(s) + 12 N aCl O3(aq) 1. 3 2:4 3.6 4.8 Fundamentals of N 4 Match each reaction to the sum of the coefficients of its net ionic reaction. For example, sum of coefficients of 2 H2 + O2 → 2 H2O is 2 + 1 + 2 = 5. If you are having trouble with this exercis 2 Fe(CIO3)3(aq) + 3 Na2CrO4(aq) → Fe2(CrO4)3(s) + 6 NaCIO3(aq) __1__ 2 Screen Reader: 2 F e(CI O3)3(aq) + 3 N a2Cr 04(a q) → F e2(Cr 04)3(s) + 6 Na Cl O3(aq) Pb(ClO3)4(aq) + 4 NaCl(aq) → PbC14(s) + 4 NaCIO3(aq) 4 Screen Reader: Pb(Cl 03)4(a q)+ 4 N a Cl(aq) → PbC14(s) + 4 N a Cl 03(aq) SnC14(aq) + 2 Na2O(aq) → SnO2(s) + 4 NaCl(aq) Screen Reader: SnC14(a q) + 2 N a20(a q) → Sn O2(s) + 4 Na Cl(aq) Fe(CIO3)2(aq) + Na2CrO4(aq) → FeCrO4(s) + 2 NaCIO3(aq) 3 Screen Reader: Fe(CI O3)2(a q) + N a2Cr 04(a q) → F e Cr 04 (s) + 2 Na Cl O3(a q) 1.3 2.4 3.6 4.8 4

Getting Started Elite Medical Academy Online Health Courses... 2__ Survey: Week 12 Partic... B Homepage - St. Peters...prometic 4-- Screen Reader: SnC14(a q) + 2 N a2O(a q) → Sn O2(s) + 4 Na Cl(a q) Fe(CIO3)2(aq) + Na2CrO4(aq) → FeCrO4(s) + 2 NaCIO3(aq) Screen Reader: Pb(Cl 03)4(a q)+ 4 N a Cl(aq) → PbC14(s) + 4 N a Cl 03(aq) SnC14(aq) + 2 Na2O(aq) → SnO2 (s) + 4 NaCl(aq) 3 Screen Reader: F e(CI O3)2(a q) + N a2Cr 04(a q) → F e Cr 04 (s) + 2 Na Cl 03(a q) 3 Pb(ClO3)2(aq) + 2 NaCl(aq) → PbCl2(s) + 2 NaClO3(aq) _2_- Screen Reader: Pb(Cl 03)2(a q)+ 2 N a Cl(aq) → PbCl2(s) + 2N a CI O3(aq) 3 Pb(ClO3)4(aq) + 4 Na3N(aq) → Pb3N4(s) + 12 NaCIO3(aq) 11 - Screen Reader: 3 Pb(CI O3)4(a q)+ 4 N a3N(a q) → Pb3N4(s) + 12 N aCl O3(aq) 1. 3 2:4 3.6 4.8 Fundamentals of N 4 Match each reaction to the sum of the coefficients of its net ionic reaction. For example, sum of coefficients of 2 H2 + O2 → 2 H2O is 2 + 1 + 2 = 5. If you are having trouble with this exercis 2 Fe(CIO3)3(aq) + 3 Na2CrO4(aq) → Fe2(CrO4)3(s) + 6 NaCIO3(aq) __1__ 2 Screen Reader: 2 F e(CI O3)3(aq) + 3 N a2Cr 04(a q) → F e2(Cr 04)3(s) + 6 Na Cl O3(aq) Pb(ClO3)4(aq) + 4 NaCl(aq) → PbC14(s) + 4 NaCIO3(aq) 4 Screen Reader: Pb(Cl 03)4(a q)+ 4 N a Cl(aq) → PbC14(s) + 4 N a Cl 03(aq) SnC14(aq) + 2 Na2O(aq) → SnO2(s) + 4 NaCl(aq) Screen Reader: SnC14(a q) + 2 N a20(a q) → Sn O2(s) + 4 Na Cl(aq) Fe(CIO3)2(aq) + Na2CrO4(aq) → FeCrO4(s) + 2 NaCIO3(aq) 3 Screen Reader: Fe(CI O3)2(a q) + N a2Cr 04(a q) → F e Cr 04 (s) + 2 Na Cl O3(a q) 1.3 2.4 3.6 4.8 4

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Getting Started Elite Medical Academy Online Health Courses... 2__ Survey: Week 12 Partic... B Homepage - St. Peters...prometic 4-- Screen Reader: SnC14(a q) + 2 N a2O(a q) → Sn O2(s) + 4 Na Cl(a q) Fe(CIO3)2(aq) + Na2CrO4(aq) → FeCrO4(s) + 2 NaCIO3(aq) Screen Reader: Pb(Cl 03)4(a q)+ 4 N a Cl(aq) → PbC14(s) + 4 N a Cl 03(aq) SnC14(aq) + 2 Na2O(aq) → SnO2 (s) + 4 NaCl(aq) 3 Screen Reader: F e(CI O3)2(a q) + N a2Cr 04(a q) → F e Cr 04 (s) + 2 Na Cl 03(a q) 3 Pb(ClO3)2(aq) + 2 NaCl(aq) → PbCl2(s) + 2 NaClO3(aq) _2_- Screen Reader: Pb(Cl 03)2(a q)+ 2 N a Cl(aq) → PbCl2(s) + 2N a CI O3(aq) 3 Pb(ClO3)4(aq) + 4 Na3N(aq) → Pb3N4(s) + 12 NaCIO3(aq) 11 - Screen Reader: 3 Pb(CI O3)4(a q)+ 4 N a3N(a q) → Pb3N4(s) + 12 N aCl O3(aq) 1. 3 2:4 3.6 4.8 Fundamentals of N 4
Transcribed Image Text:Getting Started Elite Medical Academy Online Health Courses... 2__ Survey: Week 12 Partic... B Homepage - St. Peters...prometic 4-- Screen Reader: SnC14(a q) + 2 N a2O(a q) → Sn O2(s) + 4 Na Cl(a q) Fe(CIO3)2(aq) + Na2CrO4(aq) → FeCrO4(s) + 2 NaCIO3(aq) Screen Reader: Pb(Cl 03)4(a q)+ 4 N a Cl(aq) → PbC14(s) + 4 N a Cl 03(aq) SnC14(aq) + 2 Na2O(aq) → SnO2 (s) + 4 NaCl(aq) 3 Screen Reader: F e(CI O3)2(a q) + N a2Cr 04(a q) → F e Cr 04 (s) + 2 Na Cl 03(a q) 3 Pb(ClO3)2(aq) + 2 NaCl(aq) → PbCl2(s) + 2 NaClO3(aq) _2_- Screen Reader: Pb(Cl 03)2(a q)+ 2 N a Cl(aq) → PbCl2(s) + 2N a CI O3(aq) 3 Pb(ClO3)4(aq) + 4 Na3N(aq) → Pb3N4(s) + 12 NaCIO3(aq) 11 - Screen Reader: 3 Pb(CI O3)4(a q)+ 4 N a3N(a q) → Pb3N4(s) + 12 N aCl O3(aq) 1. 3 2:4 3.6 4.8 Fundamentals of N 4
Match each reaction to the sum of the coefficients of its net ionic reaction. For example, sum of coefficients of 2 H2 + O2 → 2 H2O is 2 + 1 + 2 = 5. If you are having trouble with this exercis 2 Fe(CIO3)3(aq) + 3 Na2CrO4(aq) → Fe2(CrO4)3(s) + 6 NaCIO3(aq) __1__ 2 Screen Reader: 2 F e(CI O3)3(aq) + 3 N a2Cr 04(a q) → F e2(Cr 04)3(s) + 6 Na Cl O3(aq) Pb(ClO3)4(aq) + 4 NaCl(aq) → PbC14(s) + 4 NaCIO3(aq) 4 Screen Reader: Pb(Cl 03)4(a q)+ 4 N a Cl(aq) → PbC14(s) + 4 N a Cl 03(aq) SnC14(aq) + 2 Na2O(aq) → SnO2(s) + 4 NaCl(aq) Screen Reader: SnC14(a q) + 2 N a20(a q) → Sn O2(s) + 4 Na Cl(aq) Fe(CIO3)2(aq) + Na2CrO4(aq) → FeCrO4(s) + 2 NaCIO3(aq) 3 Screen Reader: Fe(CI O3)2(a q) + N a2Cr 04(a q) → F e Cr 04 (s) + 2 Na Cl O3(a q) 1.3 2.4 3.6 4.8 4
Transcribed Image Text:Match each reaction to the sum of the coefficients of its net ionic reaction. For example, sum of coefficients of 2 H2 + O2 → 2 H2O is 2 + 1 + 2 = 5. If you are having trouble with this exercis 2 Fe(CIO3)3(aq) + 3 Na2CrO4(aq) → Fe2(CrO4)3(s) + 6 NaCIO3(aq) __1__ 2 Screen Reader: 2 F e(CI O3)3(aq) + 3 N a2Cr 04(a q) → F e2(Cr 04)3(s) + 6 Na Cl O3(aq) Pb(ClO3)4(aq) + 4 NaCl(aq) → PbC14(s) + 4 NaCIO3(aq) 4 Screen Reader: Pb(Cl 03)4(a q)+ 4 N a Cl(aq) → PbC14(s) + 4 N a Cl 03(aq) SnC14(aq) + 2 Na2O(aq) → SnO2(s) + 4 NaCl(aq) Screen Reader: SnC14(a q) + 2 N a20(a q) → Sn O2(s) + 4 Na Cl(aq) Fe(CIO3)2(aq) + Na2CrO4(aq) → FeCrO4(s) + 2 NaCIO3(aq) 3 Screen Reader: Fe(CI O3)2(a q) + N a2Cr 04(a q) → F e Cr 04 (s) + 2 Na Cl O3(a q) 1.3 2.4 3.6 4.8 4
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