**Chemical Reaction Balancing Exercise** **Question:** What is the balanced equation for this reaction? Options: - a) \( \text{FeCl}_2(aq) + \text{Na}_2\text{S}(aq) \rightarrow \text{FeS}(s) + 2 \text{NaCl}(aq) \) ✔️ - b) \( \text{IrCl}_2(aq) + \text{Na}_2\text{S}(aq) \rightarrow \text{IrS}(s) + 2 \text{NaCl}(aq) \) - c) \( \text{FeCl}_2(aq) + \text{Na}_2\text{SO}_4(aq) \rightarrow \text{FeSO}_4(aq) + 2 \text{NaCl}(aq) \) - d) \( \text{FeCl}_3(aq) + \text{Na}_2\text{S}(aq) \rightarrow \text{FeS}(s) + \text{NaCl}(aq) \) **Answer:** The balanced equation for this reaction is: \[ \text{FeCl}_2(aq) + \text{Na}_2\text{S}(aq) \rightarrow \text{FeS}(s) + 2 \text{NaCl}(aq) \] This indicates a double displacement reaction where iron(II) chloride and sodium sulfide react in aqueous solutions to form solid iron(II) sulfide and sodium chloride. **Problem:** If you combine 27 g each of \( \text{Na}_2\text{S} \) and \( \text{FeCl}_2 \), what is the limiting reactant? Options: - \( \text{Na}_2\text{S} \) - \( \text{FeCl}_2 \) **Action:** Enter your selection and click "Submit" to see which reactant limits the reaction. **Navigation:** - Use "Submit Answer" to confirm your response. - Click "Try Another Version" if needed, with 10 attempts remaining.

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Chemical Reaction Balancing Exercise**

**Question:**
What is the balanced equation for this reaction?

Options:  
- a) \( \text{FeCl}_2(aq) + \text{Na}_2\text{S}(aq) \rightarrow \text{FeS}(s) + 2 \text{NaCl}(aq) \) ✔️  
- b) \( \text{IrCl}_2(aq) + \text{Na}_2\text{S}(aq) \rightarrow \text{IrS}(s) + 2 \text{NaCl}(aq) \)  
- c) \( \text{FeCl}_2(aq) + \text{Na}_2\text{SO}_4(aq) \rightarrow \text{FeSO}_4(aq) + 2 \text{NaCl}(aq) \)  
- d) \( \text{FeCl}_3(aq) + \text{Na}_2\text{S}(aq) \rightarrow \text{FeS}(s) + \text{NaCl}(aq) \)  

**Answer:**
The balanced equation for this reaction is:  
\[ \text{FeCl}_2(aq) + \text{Na}_2\text{S}(aq) \rightarrow \text{FeS}(s) + 2 \text{NaCl}(aq) \]

This indicates a double displacement reaction where iron(II) chloride and sodium sulfide react in aqueous solutions to form solid iron(II) sulfide and sodium chloride.

**Problem:**
If you combine 27 g each of \( \text{Na}_2\text{S} \) and \( \text{FeCl}_2 \), what is the limiting reactant?

Options:
- \( \text{Na}_2\text{S} \)
- \( \text{FeCl}_2 \)

**Action:**
Enter your selection and click "Submit" to see which reactant limits the reaction.

**Navigation:**
- Use "Submit Answer" to confirm your response.
- Click "Try Another Version" if needed, with 10 attempts remaining.
Transcribed Image Text:**Chemical Reaction Balancing Exercise** **Question:** What is the balanced equation for this reaction? Options: - a) \( \text{FeCl}_2(aq) + \text{Na}_2\text{S}(aq) \rightarrow \text{FeS}(s) + 2 \text{NaCl}(aq) \) ✔️ - b) \( \text{IrCl}_2(aq) + \text{Na}_2\text{S}(aq) \rightarrow \text{IrS}(s) + 2 \text{NaCl}(aq) \) - c) \( \text{FeCl}_2(aq) + \text{Na}_2\text{SO}_4(aq) \rightarrow \text{FeSO}_4(aq) + 2 \text{NaCl}(aq) \) - d) \( \text{FeCl}_3(aq) + \text{Na}_2\text{S}(aq) \rightarrow \text{FeS}(s) + \text{NaCl}(aq) \) **Answer:** The balanced equation for this reaction is: \[ \text{FeCl}_2(aq) + \text{Na}_2\text{S}(aq) \rightarrow \text{FeS}(s) + 2 \text{NaCl}(aq) \] This indicates a double displacement reaction where iron(II) chloride and sodium sulfide react in aqueous solutions to form solid iron(II) sulfide and sodium chloride. **Problem:** If you combine 27 g each of \( \text{Na}_2\text{S} \) and \( \text{FeCl}_2 \), what is the limiting reactant? Options: - \( \text{Na}_2\text{S} \) - \( \text{FeCl}_2 \) **Action:** Enter your selection and click "Submit" to see which reactant limits the reaction. **Navigation:** - Use "Submit Answer" to confirm your response. - Click "Try Another Version" if needed, with 10 attempts remaining.
Expert Solution
Step 1

According to the Law of conservation of mass " all atoms of different elements must be equal on both sides in a chemical reaction" 

Number of moles = mass/molar mass 

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