Assigned Tr Trial 1 DATA $4409 Mass of unknown 3410265 Mass of beaker + water Mass of empty beaker 341, 289 19. Loc= ,9984052gkm? Mass of displaced water Temperature of water K Density of water (lookup @ T) 341,8151 ,3418 ISAL 7341.! Volume of water Liters of gas (mostly CO2) Barometric Pressure mm Hg Vapor Pressure H20 (look up @ T) 719.4mlHtg Partial Pressure of CO2
Ideal and Real Gases
Ideal gases obey conditions of the general gas laws under all states of pressure and temperature. Ideal gases are also named perfect gases. The attributes of ideal gases are as follows,
Gas Laws
Gas laws describe the ways in which volume, temperature, pressure, and other conditions correlate when matter is in a gaseous state. The very first observations about the physical properties of gases was made by Robert Boyle in 1662. Later discoveries were made by Charles, Gay-Lussac, Avogadro, and others. Eventually, these observations were combined to produce the ideal gas law.
Gaseous State
It is well known that matter exists in different forms in our surroundings. There are five known states of matter, such as solids, gases, liquids, plasma and Bose-Einstein condensate. The last two are known newly in the recent days. Thus, the detailed forms of matter studied are solids, gases and liquids. The best example of a substance that is present in different states is water. It is solid ice, gaseous vapor or steam and liquid water depending on the temperature and pressure conditions. This is due to the difference in the intermolecular forces and distances. The occurrence of three different phases is due to the difference in the two major forces, the force which tends to tightly hold molecules i.e., forces of attraction and the disruptive forces obtained from the thermal energy of molecules.
Solve for the Number of moles of the unknown with the given data. I do not no the given substance
Mass of the unknown, m = 0.5940 g
Partial pressure of CO2 , P= 719.4 mm Hg = 719.4 / 760 = 0.9465 atm
1 atm = 760 mm Hg
Volume of the gas, V = 0.3418 L
Temperature of the gas = 19.2oC = 19.2+273.15 = 292.35 K
R = 0.082057 L atm mol-1K-1
Find n from the following data
Step by step
Solved in 2 steps