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**Question 3** If a gas now occupies 16.7 L under 2.03 atm, what would the original pressure of the gas have been if it occupied 40.2 L? _____ atm --- *Note:* This question involves using Boyle’s Law, which states that the pressure of a gas is inversely proportional to its volume when temperature remains constant. The formula is \( P_1V_1 = P_2V_2 \). Given the current volume (16.7 L) and pressure (2.03 atm), you need to find the original pressure when the volume was 40.2 L.

**Question 3** If a gas now occupies 16.7 L under 2.03 atm, what would the original pressure of the gas have been if it occupied 40.2 L? _____ atm --- *Note:* This question involves using Boyle’s Law, which states that the pressure of a gas is inversely proportional to its volume when temperature remains constant. The formula is \( P_1V_1 = P_2V_2 \). Given the current volume (16.7 L) and pressure (2.03 atm), you need to find the original pressure when the volume was 40.2 L.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Question 3** If a gas now occupies 16.7 L under 2.03 atm, what would the original pressure of the gas have been if it occupied 40.2 L? _____ atm --- *Note:* This question involves using Boyle’s Law, which states that the pressure of a gas is inversely proportional to its volume when temperature remains constant. The formula is \( P_1V_1 = P_2V_2 \). Given the current volume (16.7 L) and pressure (2.03 atm), you need to find the original pressure when the volume was 40.2 L.
Transcribed Image Text:**Question 3** If a gas now occupies 16.7 L under 2.03 atm, what would the original pressure of the gas have been if it occupied 40.2 L? _____ atm --- *Note:* This question involves using Boyle’s Law, which states that the pressure of a gas is inversely proportional to its volume when temperature remains constant. The formula is \( P_1V_1 = P_2V_2 \). Given the current volume (16.7 L) and pressure (2.03 atm), you need to find the original pressure when the volume was 40.2 L.
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