Identify the major organic product generated from the reaction shown. D 1 + enantiomer CH3 none of these CH3 D || D + enantiomer D₂ Pd ? CH3 H D + enantiomer IM D CH3 What is wrong with the following mechanism? H₂O Br Br The arrow indicating the formation of the C-Br bond (nucleophilic attack) should start at the bromide anion. An arrow is also needed to indicate the loss of the leaving group. None of these The arrow should be removing a proton from the H2O group. There is no leaving group, so there should be no arrows.

Identify the major organic product generated from the reaction shown. D 1 + enantiomer CH3 none of these CH3 D || D + enantiomer D₂ Pd ? CH3 H D + enantiomer IM D CH3 What is wrong with the following mechanism? H₂O Br Br The arrow indicating the formation of the C-Br bond (nucleophilic attack) should start at the bromide anion. An arrow is also needed to indicate the loss of the leaving group. None of these The arrow should be removing a proton from the H2O group. There is no leaving group, so there should be no arrows.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

Pls help ASAP on both.

Identify the major organic product generated from the reaction shown.
D
1
+ enantiomer
CH3
none of these
CH3
D
||
D
+ enantiomer
D₂
Pd
?
CH3
H
D
+ enantiomer
IM
D
CH3

What is wrong with the following mechanism?
H₂O
Br
Br
The arrow indicating the formation of the C-Br bond (nucleophilic attack) should
start at the bromide anion.
An arrow is also needed to indicate the loss of the leaving group.
None of these
The arrow should be removing a proton from the H2O group.
There is no leaving group, so there should be no arrows.

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Step 1: Syn addition of D2

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Step 2: Bromide anion attack to the carbon which is bearing the leaving group -OH2+

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