### Topic: Bond Angles in the Iodine Tetrachloride Ion \((ICl_4^-)\) #### Question: What is the expected Cl-I-Cl bond angle in the iodine tetrachloride ion \((ICl_4^-)\)? #### Diagram Description: The diagram shows the structural representation of the iodine tetrachloride ion \((ICl_4^-)\). It displays an iodine (I) atom centrally bonded to four chlorine (Cl) atoms. The chlorine atoms are positioned around the iodine atom in a plane, each with three lone pairs of electrons. The iodine atom also has two lone pairs on the perpendicular axis to the square plane of the chlorines, making the structure square planar. The single negative charge is indicated outside the brackets that enclose the entire structure. #### Answer Choices: 1. 90 2. < 109.5 3. 109.5 4. 120 ### Explanation: The iodine tetrachloride ion \((ICl_4^-)\) adopts a square planar geometry due to the presence of two lone pairs of electrons on the central iodine atom. According to the VSEPR (Valence Shell Electron Pair Repulsion) theory, the lone pairs are positioned opposite each other, reducing the repulsion between them, which arranges the chlorine atoms in a planar configuration around the iodine. Given this geometry: - The expected Cl-I-Cl bond angle in a square planar geometry is \(90^\circ\). **Correct Answer: 90** ### Key Concepts: - **VSEPR Theory**: This theory helps predict the shape of the molecule by minimizing the repulsion between electron pairs around the central atom. - **Square Planar Geometry**: This specific arrangement results in bond angles of \(90^\circ\) between adjacent bonding pairs. Understanding the bond angles in molecular structures such as \((ICl_4^-)\) assists in comprehending the spatial arrangement of atoms, which is crucial for predicting the physical and chemical properties of the molecule.

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### Topic: Bond Angles in the Iodine Tetrachloride Ion \((ICl_4^-)\)

#### Question:
What is the expected Cl-I-Cl bond angle in the iodine tetrachloride ion \((ICl_4^-)\)?

#### Diagram Description:
The diagram shows the structural representation of the iodine tetrachloride ion \((ICl_4^-)\). It displays an iodine (I) atom centrally bonded to four chlorine (Cl) atoms. The chlorine atoms are positioned around the iodine atom in a plane, each with three lone pairs of electrons. The iodine atom also has two lone pairs on the perpendicular axis to the square plane of the chlorines, making the structure square planar. The single negative charge is indicated outside the brackets that enclose the entire structure.

#### Answer Choices:
1. 90
2. < 109.5
3. 109.5
4. 120

### Explanation:
The iodine tetrachloride ion \((ICl_4^-)\) adopts a square planar geometry due to the presence of two lone pairs of electrons on the central iodine atom. According to the VSEPR (Valence Shell Electron Pair Repulsion) theory, the lone pairs are positioned opposite each other, reducing the repulsion between them, which arranges the chlorine atoms in a planar configuration around the iodine.

Given this geometry:
- The expected Cl-I-Cl bond angle in a square planar geometry is \(90^\circ\).

**Correct Answer: 90**

### Key Concepts:
- **VSEPR Theory**: This theory helps predict the shape of the molecule by minimizing the repulsion between electron pairs around the central atom.
- **Square Planar Geometry**: This specific arrangement results in bond angles of \(90^\circ\) between adjacent bonding pairs.

Understanding the bond angles in molecular structures such as \((ICl_4^-)\) assists in comprehending the spatial arrangement of atoms, which is crucial for predicting the physical and chemical properties of the molecule.
Transcribed Image Text:### Topic: Bond Angles in the Iodine Tetrachloride Ion \((ICl_4^-)\) #### Question: What is the expected Cl-I-Cl bond angle in the iodine tetrachloride ion \((ICl_4^-)\)? #### Diagram Description: The diagram shows the structural representation of the iodine tetrachloride ion \((ICl_4^-)\). It displays an iodine (I) atom centrally bonded to four chlorine (Cl) atoms. The chlorine atoms are positioned around the iodine atom in a plane, each with three lone pairs of electrons. The iodine atom also has two lone pairs on the perpendicular axis to the square plane of the chlorines, making the structure square planar. The single negative charge is indicated outside the brackets that enclose the entire structure. #### Answer Choices: 1. 90 2. < 109.5 3. 109.5 4. 120 ### Explanation: The iodine tetrachloride ion \((ICl_4^-)\) adopts a square planar geometry due to the presence of two lone pairs of electrons on the central iodine atom. According to the VSEPR (Valence Shell Electron Pair Repulsion) theory, the lone pairs are positioned opposite each other, reducing the repulsion between them, which arranges the chlorine atoms in a planar configuration around the iodine. Given this geometry: - The expected Cl-I-Cl bond angle in a square planar geometry is \(90^\circ\). **Correct Answer: 90** ### Key Concepts: - **VSEPR Theory**: This theory helps predict the shape of the molecule by minimizing the repulsion between electron pairs around the central atom. - **Square Planar Geometry**: This specific arrangement results in bond angles of \(90^\circ\) between adjacent bonding pairs. Understanding the bond angles in molecular structures such as \((ICl_4^-)\) assists in comprehending the spatial arrangement of atoms, which is crucial for predicting the physical and chemical properties of the molecule.
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