Chemical process with purge: The production of ammonia is shown in the process below. Given the molar flow rates of streams 3, 4, and 5 in Table B.1 below, what are the split fractions for stream 3 going to streams 4 and 5? Table B.1 Mole flow rates at recycle split in ammonia process Component Stream 3 (mol/hr) Stream 4 (mol/hr) Stream 5 (mol/hr) Nitrogen N₂ 133 20 113 Hydrogen H₂ 120 Inert 100 800 667 680 567 RXN 1: Nitrogen (N) + Hydrogen (H) → Ammonia (AM) N₂ + 3H₂ → 2NH3
Chemical process with purge: The production of ammonia is shown in the process below. Given the molar flow rates of streams 3, 4, and 5 in Table B.1 below, what are the split fractions for stream 3 going to streams 4 and 5? Table B.1 Mole flow rates at recycle split in ammonia process Component Stream 3 (mol/hr) Stream 4 (mol/hr) Stream 5 (mol/hr) Nitrogen N₂ 133 20 113 Hydrogen H₂ 120 Inert 100 800 667 680 567 RXN 1: Nitrogen (N) + Hydrogen (H) → Ammonia (AM) N₂ + 3H₂ → 2NH3
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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split fraction problem plz help
![Chemical process with purge: The production of ammonia is shown in the process below. Given the molar flow rates of
streams 3, 4, and 5 in Table B.1 below, what are the split fractions for stream 3 going to streams 4 and 5?
FEED
nN,O = 120 mol/hr N2
nн,0 = 420 mol/hr H2
no 100 mol/hr I
Table B.1 Mole flow rates at recycle split in ammonia process
Component Stream 3 (mol/hr) Stream 4 (mol/hr) Stream 5 (mol/hr)
Nitrogen N₂
133
20
113
Hydrogen H₂
120
680
Inert
100
567
STREAM 1
H
N=233 mul
OH = 1100m
n1=667 mil
a. Split fraction streams 3 to 4
b. Split fraction streams 3 to 5
RXN 1: Nitrogen (N) + Hydrogen (H) → Ammonia (AM)
N₂ + 3H₂ → 2NH3
ON=113
nH =680
^+ =
567
800
667
Reaction
Process
RECYCLE
STREAM 5
STREAM 2
N=133
nH = 800
7[=667
MAM = 200
(133+800+667)-(20+120 +100)
100
(113 +800+667)-(113 +680 +567)
100
STREAM 3
N=133
THE 800
22=667
18%
2.2%
GAS ONLY
RECYCLE
Condenser
(liquid &
vapor separator)
PURGE
STREAM 4
nN=20
nh:120
DI = 100
LIQUID
PRODUCT
NAM = 200 mol/hr AM
Zero all other
components](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd47fc2c3-8f4b-4085-b234-bc909be774e3%2Fb2358078-2340-4eb6-a398-2dc39c3d2efc%2Fnx4zpjo_processed.png&w=3840&q=75)
Transcribed Image Text:Chemical process with purge: The production of ammonia is shown in the process below. Given the molar flow rates of
streams 3, 4, and 5 in Table B.1 below, what are the split fractions for stream 3 going to streams 4 and 5?
FEED
nN,O = 120 mol/hr N2
nн,0 = 420 mol/hr H2
no 100 mol/hr I
Table B.1 Mole flow rates at recycle split in ammonia process
Component Stream 3 (mol/hr) Stream 4 (mol/hr) Stream 5 (mol/hr)
Nitrogen N₂
133
20
113
Hydrogen H₂
120
680
Inert
100
567
STREAM 1
H
N=233 mul
OH = 1100m
n1=667 mil
a. Split fraction streams 3 to 4
b. Split fraction streams 3 to 5
RXN 1: Nitrogen (N) + Hydrogen (H) → Ammonia (AM)
N₂ + 3H₂ → 2NH3
ON=113
nH =680
^+ =
567
800
667
Reaction
Process
RECYCLE
STREAM 5
STREAM 2
N=133
nH = 800
7[=667
MAM = 200
(133+800+667)-(20+120 +100)
100
(113 +800+667)-(113 +680 +567)
100
STREAM 3
N=133
THE 800
22=667
18%
2.2%
GAS ONLY
RECYCLE
Condenser
(liquid &
vapor separator)
PURGE
STREAM 4
nN=20
nh:120
DI = 100
LIQUID
PRODUCT
NAM = 200 mol/hr AM
Zero all other
components
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