CHEMICAL EQUILIBRIUM: FINDING A CONSTANT Solution No 1 2 3 0.200 M Fe (NO3)3 in 0.1 M HNO3 [ml] 9.0 9.0 9.0 0.00200 MKSCN [ml] 8.0 10.0 12.0 0.10 M HNO3 [ml] 8.0 6.0 4.0 Molarity 2+ FeSCN (aq) calculate
CHEMICAL EQUILIBRIUM: FINDING A CONSTANT Solution No 1 2 3 0.200 M Fe (NO3)3 in 0.1 M HNO3 [ml] 9.0 9.0 9.0 0.00200 MKSCN [ml] 8.0 10.0 12.0 0.10 M HNO3 [ml] 8.0 6.0 4.0 Molarity 2+ FeSCN (aq) calculate
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter14: Chemical Equilibrium
Section: Chapter Questions
Problem 14.2QE: Describe a nonchemical system that is in equilibrium, and explain how the principles of equilibrium...
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![CHEMICAL EQUILIBRIUM: FINDING A CONSTANT
2
3
st
4
Solution No
1
5
0.200 M Fe
(NO3)3
in 0.1 M
HNO3
[ml]
9.0
9.0
9.0
9.0
9.0
0.00200
MKSCN
[ml]
8.0
10.0
12.0
14.0
16.0
0.10 M
HNO3
[ml]
8.0
6.0
4.0
2.0
0.0
?
?
?
Molarity
2+
FeSCN (aq)
calculate
?
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Transcribed Image Text:CHEMICAL EQUILIBRIUM: FINDING A CONSTANT
2
3
st
4
Solution No
1
5
0.200 M Fe
(NO3)3
in 0.1 M
HNO3
[ml]
9.0
9.0
9.0
9.0
9.0
0.00200
MKSCN
[ml]
8.0
10.0
12.0
14.0
16.0
0.10 M
HNO3
[ml]
8.0
6.0
4.0
2.0
0.0
?
?
?
Molarity
2+
FeSCN (aq)
calculate
?
?
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