Chemical analysis reveals that a sample of dioxin contains 14.29g of carbon, 1.20g of hydrogen, and 9.52g of oxygen. Dioxin has a molar mass of 84.07g/mol. what is its molecular formula?

Q: What is the molecular formula of an unknown compound which is composed of 57.14% carbon, 27.18 %…

A: Molecular formula = (Empirical formula)n where n = No of empirical formula components that combine…

Q: An antifreeze and coolant widely used in automobile engines is 38.7% carbon, 9.7% hydrogen, and…

A: Given: antifreeze and coolant widely used in automobile engines is: 38.7% carbon 9.7% hydrogen…

Q: The empirical formula for xylene is C4H5(l), and its molar mass is 106 g/mol. What is the molecular…

A: Given :-  Molar mass of xylene = 106 g/mol  Empirical formula = C4H5   To determine :-  Its…

Q: A compound was found to contain 115.49g of Ca, 92.16 g of O, and 5.82 g of H. What is the total mass…

A: mass of Ca = 115.49g mass of O = 92.16 g mass of H =  5.82 g  Molar mass of Ca = 40.078 g/molMolar…

Q: A 3.000 g sample of a gaseous compound was found to contain 2.560 g of carbon and  0.440 g of…

A: To answer this first of all we have to convert grams into moles and we have to determine the simple…

Q: An organic compound has an empirical formula CH2 and a molar mass of 112.21 g/mol. How many H atoms…

A: an empirical formula CH2  empirical mass = (12 x 1 ) + (1 x 2)= 14  n = molar mass / empirical mass…

Q: An ionic compound was formed by combining 8.289 g of copper (Cu) with 1.218 g of nitrogen (N). What…

A: Given that, Mass of copper Cu = 8.289 g Moles of Cu in 8.289 g = 8.289 g/63.546 g/mol = 0.13044 mol…

Q: An organic compound used as a food additive in beverages and baking powders, is composed of 41.39%…

A: Given  % C  = 41.39 % H = 3.47  % O = 100 -( 41.39 + 3.47 ) %         = 55.14 %  Empirical Formula =…

Q: A 50.00 g sample of an organic compound containing only C, H and O is analyzed by combustion…

A: The objective of the question is to determine the empirical formula of the organic compound…

Q: A certain sample of butane fuel (C4H10) was analyzed and found to contain 1.8 x 1024 hydrogen atoms.…

A: Octane is a hydrocarbon of alkane category. Its general formula is CnH2n+2 where n is an integer.The…

Q: he empirical formula for trichloroisocyanuric acid, the active ingredient in many household…

A:

Q: Butanol is 64.81% carbon, 21.59% oxygen, and 13.60% hydrogen by mass. What is the molecular formula…

A: Given that the Butanol is 64.81% carbon, 21.59 % oxygen and 13.60 % hydrogen by mass. The molar mass…

Q: A compound contains 47.08% carbon, 6.59% hydrogen, and 46.33% chlorine by mass; the molar mass of…

A:

Q: will

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Q: The empirical formula of an unknown compound was determined to be C4H9. Its molar mass is 114.22…

A: Empirical formula of the compound is C4H9. Calculation of empirical formula mass:…

Q: A compound contains 78.14% B and 21.86% H by mass and has a molar mass of 27.67 g/mol. What is the…

A: mass % of B = 78.14 %mass % of H = 21.86 % mass of hydrogen in 1 mole (27.67 g) of the compound = ?

Q: a compound contains 47.08% C, 6.59% Hydrogen and 46.33% Cl by mass. The molar mass of the compound…

A: T

Q: The empirical formula for a compound is CH2O, and the molar mass is 180.2 g/mol. Which is the…

A: The empirical formula of compound  = CH2O The molar mass of Molecule = 180.2 g/mol   To get the…

Q: osmium by mass. a) If you assume 100.0 g of the compound, what is the mass in grams of osmium that…

A: Since you have posted a question with multiple sub- parts, we will solve first three sub- parts for…

Q: Sugars can be metabolized to lactic acid by Streptococcus mutans, a bacterium that lives in the oral…

A: Given : Mass percent of C = 40.0 % Mass percent of H = 6.71 % Mass percent of O = 53.3 % And molar…

Q: Xylene, an organic compound that is a major component of many gasoline blends, contains carbon and…

A: Xylene, an organic compound and contains carbon and hydrogen only. Mass of xylene sample=17.12 mg…

Q: A 60.0 g sample of tetraethyl lead, a gasoline additive, is found to contain 38.43 g lead, 17.83 g…

A: The empirical formula of a compound will give us the integer ratio corresponding to the atoms…

Q: etraphenylporphyrin is a synthetic compound that resembles naturally occurring porphyrins.…

A: Step 1: % by mass of C = 85.96 % % by mass of H = 4.92 % % by mass of N = 100-(85.96 + 4.92)…

Q: A compound contains only carbon, hydrogen, and oxygen. Combustion of 10.68 mg of the compound yields…

A:

Q: A molecule has an empirical formula of CH 2O and a molar mass of 179.9 g/mol. What is the molecular…

A: The empirical formula describes the smallest whole number ratio of atoms present in a compound.…

Q: The characteristic odor of decaying flesh is due to the presence of various nitrogen-containing…

A: The molar mass of any substance is the mass present in one mole of the substance and the molecular…

Q: The empirical formula of an unknown compound is CH and the molar mass of compound is 78.11 g/mol.…

A:

Q: Quinine is used to treat malaria and has a molar mass of 325g/mol. If the empirical formula is…

A:

Q: An unknown compound has the following chemical formula: Mn (CN) where x stands for a whole number.…

A: Mole of carbon= 5.9Mole of Mn = 3.0

Q: The empirical formula of a compound is C4H9. It's molecular mass is 114g/Mol. What is its molecular…

A: We have to predict the molecular formula.

Q: A combustion analysis of 5.214 g of a compound yields 5.34 g CO, 1.09 g HO, and 1.70 g N. If the…

A: Correction: It should be CO2  not CO It should be H2O not HO It should be N2 not N Given, Mass of…

Q: A 3.000 g sample of a gaseous compound was found to contain 2.560 g of carbon and 0.440 g of…

A: To solve thia problem first we have to calculate the number mole of C and H in the given sample.  By…

Q: A compound containing carbon and hydrogen contains 4.75 g of carbon and 0.80 g of hydrogen.  The…

A: Empirical formula is the simplest whole number ratio of the elements present in the molecule while…

Mole Concept

Mole concept is a method to determine the amount of any substance that consists of some elemental particles using a grouping unit called ‘mole’. The mole concept enables one to handle the large amount of small elementary particles. The mole concept can be used in many calculations related to mole calculation, molar amount, mole ratio, and so on, which are significant in chemistry.