Homework Help is Here – Start Your Trial Now!
Engineering
Computer Science
Checkpoint 3.59 Assume the variables name1 and name2 reference two different String objects, containing different strings. Write code that displays the strings referenced by these variables in alphabetical order. System.out.println(name1); System.out.println(name2); } else { System.out.println(name2); System.out.println(name1); } Fill in the blank. + namel + alphabetically.");| + comes before

Checkpoint 3.59 Assume the variables name1 and name2 reference two different String objects, containing different strings. Write code that displays the strings referenced by these variables in alphabetical order. System.out.println(name1); System.out.println(name2); } else { System.out.println(name2); System.out.println(name1); } Fill in the blank. + namel + alphabetically.");| + comes before

Database System Concepts
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
See similar textbooks
icon
Related questions
Question

java

### Checkpoint 3.59 #### Problem Statement: Assume the variables `name1` and `name2` reference two different `String` objects, containing different strings. Write code that displays the strings referenced by these variables in alphabetical order. ```java ________ { System.out.println(name1); System.out.println(name2); } else { System.out.println(name2); System.out.println(name1); } ``` #### Task: Fill in the blank. #### Incorrect Attempt: An attempt was made to fill in the blank with: ```java + " comes before " + name1 + " alphabetically."); ``` This resulted in an incorrect response, as marked by the red 'X' and the message "Incorrect. Try again." ### Solution Explanation: To correctly display `name1` and `name2` in alphabetical order, you need to compare the two strings using the `compareTo` method of the `String` class. Here is the correct code: ```java if (name1.compareTo(name2) < 0) { System.out.println(name1); System.out.println(name2); } else { System.out.println(name2); System.out.println(name1); } ``` ### Detailed Explanation: 1. **String Comparison:** - `name1.compareTo(name2) < 0` checks if `name1` is alphabetically before `name2`. The `compareTo` method returns: - A negative integer if `name1` comes before `name2`. - Zero if `name1` and `name2` are equal. - A positive integer if `name1` comes after `name2`. 2. **If-Else Structure:** - If the condition `name1.compareTo(name2) < 0` is true, `name1` is printed first followed by `name2`. - If the condition is false, `name2` is printed first followed by `name1`. This ensures that the strings are always printed in alphabetical order. Remember to always test the logic with different strings to ensure correctness.
Transcribed Image Text:### Checkpoint 3.59 #### Problem Statement: Assume the variables `name1` and `name2` reference two different `String` objects, containing different strings. Write code that displays the strings referenced by these variables in alphabetical order. ```java ________ { System.out.println(name1); System.out.println(name2); } else { System.out.println(name2); System.out.println(name1); } ``` #### Task: Fill in the blank. #### Incorrect Attempt: An attempt was made to fill in the blank with: ```java + " comes before " + name1 + " alphabetically."); ``` This resulted in an incorrect response, as marked by the red 'X' and the message "Incorrect. Try again." ### Solution Explanation: To correctly display `name1` and `name2` in alphabetical order, you need to compare the two strings using the `compareTo` method of the `String` class. Here is the correct code: ```java if (name1.compareTo(name2) < 0) { System.out.println(name1); System.out.println(name2); } else { System.out.println(name2); System.out.println(name1); } ``` ### Detailed Explanation: 1. **String Comparison:** - `name1.compareTo(name2) < 0` checks if `name1` is alphabetically before `name2`. The `compareTo` method returns: - A negative integer if `name1` comes before `name2`. - Zero if `name1` and `name2` are equal. - A positive integer if `name1` comes after `name2`. 2. **If-Else Structure:** - If the condition `name1.compareTo(name2) < 0` is true, `name1` is printed first followed by `name2`. - If the condition is false, `name2` is printed first followed by `name1`. This ensures that the strings are always printed in alphabetical order. Remember to always test the logic with different strings to ensure correctness.
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 1 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Knowledge Booster
Introduction to computer system
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, computer-science and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Database System Concepts
Database System Concepts
Computer Science
ISBN:
9780078022159
Author:
Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:
McGraw-Hill Education
Starting Out with Python (4th Edition)
Starting Out with Python (4th Edition)
Computer Science
ISBN:
9780134444321
Author:
Tony Gaddis
Publisher:
PEARSON
Digital Fundamentals (11th Edition)
Digital Fundamentals (11th Edition)
Computer Science
ISBN:
9780132737968
Author:
Thomas L. Floyd
Publisher:
PEARSON
C How to Program (8th Edition)
C How to Program (8th Edition)
Computer Science
ISBN:
9780133976892
Author:
Paul J. Deitel, Harvey Deitel
Publisher:
PEARSON
Database Systems: Design, Implementation, & Manag…
Database Systems: Design, Implementation, & Manag…
Computer Science
ISBN:
9781337627900
Author:
Carlos Coronel, Steven Morris
Publisher:
Cengage Learning
Programmable Logic Controllers
Programmable Logic Controllers
Computer Science
ISBN:
9780073373843
Author:
Frank D. Petruzella
Publisher:
McGraw-Hill Education
SEE MORE TEXTBOOKS