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Check that the point (1, 1,2) lies on the given surface. Then, viewing the surface as a level surface for a function f(z, y, z)ind a vector normal to the surface and an equation for the tangent plane to the surface at (1, 1, 2). 42²-4y²+²=4 vector normal = tangent plane: Z=

Check that the point (1, 1,2) lies on the given surface. Then, viewing the surface as a level surface for a function f(z, y, z)ind a vector normal to the surface and an equation for the tangent plane to the surface at (1, 1, 2). 42²-4y²+²=4 vector normal = tangent plane: Z=

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Check that the point (1,1,2) lies on the given surface. Then, viewing the surface as a level surface for a function f(z,y, 2)ind a vector normal to the surface and an equation for the tangent plane to the surface at (1, 1, 2). 42²-4y²+²=4 vector normal = tangent plane: Z=
Transcribed Image Text:Check that the point (1,1,2) lies on the given surface. Then, viewing the surface as a level surface for a function f(z,y, 2)ind a vector normal to the surface and an equation for the tangent plane to the surface at (1, 1, 2). 42²-4y²+²=4 vector normal = tangent plane: Z=
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