Check that the point (1, 1,2) lies on the given surface. Then, viewing the surface as a level surface for a function f(z, y, z)ind a vector normal to the surface and an equation for the tangent plane to the surface at (1, 1, 2). 42²-4y²+²=4 vector normal = tangent plane: Z=
Check that the point (1, 1,2) lies on the given surface. Then, viewing the surface as a level surface for a function f(z, y, z)ind a vector normal to the surface and an equation for the tangent plane to the surface at (1, 1, 2). 42²-4y²+²=4 vector normal = tangent plane: Z=
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter11: Topics From Analytic Geometry
Section11.4: Plane Curves And Parametric Equations
Problem 33E
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