Check that the point (−1, 1, 3) lies on the given surface. Then, viewing the surface as a level surface for a function f(x, y, z), find a vector normal to the surface and an equation for the tangent plane to the surface at (−1, 1, 3). 2x² − 3y² + 2z²: = 17

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Check that the point (−1, 1, 3) lies on the given surface. Then, viewing the surface as a level surface for a
function f(x, y, z), find a vector normal to the surface and an equation for the tangent plane to the surface at
(−1, 1, 3).
vector normal =
tangent plane:
z =
2x² − 3y² + 2z² = 17
Transcribed Image Text:Check that the point (−1, 1, 3) lies on the given surface. Then, viewing the surface as a level surface for a function f(x, y, z), find a vector normal to the surface and an equation for the tangent plane to the surface at (−1, 1, 3). vector normal = tangent plane: z = 2x² − 3y² + 2z² = 17
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