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Check My Work ne inside width of an air duct is 11.45 inches. The duct is made of 26-guage metal, which is o.o18 inch thick. Find the outside width in inches of e duct to 2 decimal places. O a. 11.48 O b. 11.49 O c. 11.5 O d. 11.47

Check My Work ne inside width of an air duct is 11.45 inches. The duct is made of 26-guage metal, which is o.o18 inch thick. Find the outside width in inches of e duct to 2 decimal places. O a. 11.48 O b. 11.49 O c. 11.5 O d. 11.47

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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**Question:** The inside width of an air duct is 11.45 inches. The duct is made of 26-gauge metal, which is 0.018 inch thick. Find the outside width in inches of the duct to 2 decimal places. **Options:** a. 11.48 b. 11.49 c. 11.5 d. 11.47 **Solution Explanation:** To find the outside width of the duct, add the thickness of the metal to both sides of the inside width. Since the metal is 0.018 inch thick, it adds a total of 0.036 inches to the inside width (0.018 inches on each side). **Outside Width Calculation:** Inside Width = 11.45 inches Total Metal Thickness = 0.036 inches Outside Width = Inside Width + Total Metal Thickness = 11.45 + 0.036 = 11.486 inches Rounded to two decimal places, the outside width is **11.49 inches**. Thus, the correct answer is **b. 11.49**.
Transcribed Image Text:**Question:** The inside width of an air duct is 11.45 inches. The duct is made of 26-gauge metal, which is 0.018 inch thick. Find the outside width in inches of the duct to 2 decimal places. **Options:** a. 11.48 b. 11.49 c. 11.5 d. 11.47 **Solution Explanation:** To find the outside width of the duct, add the thickness of the metal to both sides of the inside width. Since the metal is 0.018 inch thick, it adds a total of 0.036 inches to the inside width (0.018 inches on each side). **Outside Width Calculation:** Inside Width = 11.45 inches Total Metal Thickness = 0.036 inches Outside Width = Inside Width + Total Metal Thickness = 11.45 + 0.036 = 11.486 inches Rounded to two decimal places, the outside width is **11.49 inches**. Thus, the correct answer is **b. 11.49**.
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