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Chebyshev center Example: find the Chebyshev center of the polyhedron defined by the following inequalities: 2xy + 2z ≤ 2, -x +2y + 4z ≤ 16, x + 2y - 2z ≤ 8, x ≥ 0, y ≥ 0, z ≥ 0 0 0.0 2 0.5 1.0 1.5 X 2.0 4-19 Example: building a house A small sample: Let ti, to, tm, tn, tt, to be start times of the associated tasks. Now use the graph to write the dependency constraints: 0,3 FINISH • Task s can't start until tasks o $,2 Source: HBR 1963 CARPENTRY 43 FINISH FLOORING m,1 VARNISH FLOORS KITCHEN FIXTURES n,2 13 PAINT • Tasks o, m, and n can't start until task / is finished, and task / takes 3 days to finish. So the constraints are: ti +3≤ to, ti +3 ≤ tm, ti +3 ≤ tn FINISH PLUMBING • Task t can't start until tasks m and n are finished. Therefore: tm +1 ≤ tt, tn + 2 ≤ tt, and t are finished. Therefore: to +3≤ts, tt + 3 ≤ ts 4-24

Chebyshev center Example: find the Chebyshev center of the polyhedron defined by the following inequalities: 2xy + 2z ≤ 2, -x +2y + 4z ≤ 16, x + 2y - 2z ≤ 8, x ≥ 0, y ≥ 0, z ≥ 0 0 0.0 2 0.5 1.0 1.5 X 2.0 4-19 Example: building a house A small sample: Let ti, to, tm, tn, tt, to be start times of the associated tasks. Now use the graph to write the dependency constraints: 0,3 FINISH • Task s can't start until tasks o $,2 Source: HBR 1963 CARPENTRY 43 FINISH FLOORING m,1 VARNISH FLOORS KITCHEN FIXTURES n,2 13 PAINT • Tasks o, m, and n can't start until task / is finished, and task / takes 3 days to finish. So the constraints are: ti +3≤ to, ti +3 ≤ tm, ti +3 ≤ tn FINISH PLUMBING • Task t can't start until tasks m and n are finished. Therefore: tm +1 ≤ tt, tn + 2 ≤ tt, and t are finished. Therefore: to +3≤ts, tt + 3 ≤ ts 4-24

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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jupyter nootebook python by julia: find output value: value(t1), value(t0),value(tm), value(tn),value(tt),value(ts),objective_value(model)?

Modify your models and coding of Chebyshev center and building a house to get the right anwsers. 

# Given matrix A and vector b
A = [2 -1 2; -1 2 4; 1 2 -2; -1 0 0; 0 -1 0; 0 0 -1]
b = [2; 16; 8; 0; 0; 0]

Chebyshev center Example: find the Chebyshev center of the polyhedron defined by the following inequalities: 2xy + 2z ≤ 2, -x +2y + 4z ≤ 16, x + 2y - 2z ≤ 8, x ≥ 0, y ≥ 0, z ≥ 0 0 0.0 2 0.5 1.0 1.5 X 2.0 4-19
Transcribed Image Text:Chebyshev center Example: find the Chebyshev center of the polyhedron defined by the following inequalities: 2xy + 2z ≤ 2, -x +2y + 4z ≤ 16, x + 2y - 2z ≤ 8, x ≥ 0, y ≥ 0, z ≥ 0 0 0.0 2 0.5 1.0 1.5 X 2.0 4-19
Example: building a house A small sample: Let ti, to, tm, tn, tt, to be start times of the associated tasks. Now use the graph to write the dependency constraints: 0,3 FINISH • Task s can't start until tasks o $,2 Source: HBR 1963 CARPENTRY 43 FINISH FLOORING m,1 VARNISH FLOORS KITCHEN FIXTURES n,2 13 PAINT • Tasks o, m, and n can't start until task / is finished, and task / takes 3 days to finish. So the constraints are: ti +3≤ to, ti +3 ≤ tm, ti +3 ≤ tn FINISH PLUMBING • Task t can't start until tasks m and n are finished. Therefore: tm +1 ≤ tt, tn + 2 ≤ tt, and t are finished. Therefore: to +3≤ts, tt + 3 ≤ ts 4-24
Transcribed Image Text:Example: building a house A small sample: Let ti, to, tm, tn, tt, to be start times of the associated tasks. Now use the graph to write the dependency constraints: 0,3 FINISH • Task s can't start until tasks o $,2 Source: HBR 1963 CARPENTRY 43 FINISH FLOORING m,1 VARNISH FLOORS KITCHEN FIXTURES n,2 13 PAINT • Tasks o, m, and n can't start until task / is finished, and task / takes 3 days to finish. So the constraints are: ti +3≤ to, ti +3 ≤ tm, ti +3 ≤ tn FINISH PLUMBING • Task t can't start until tasks m and n are finished. Therefore: tm +1 ≤ tt, tn + 2 ≤ tt, and t are finished. Therefore: to +3≤ts, tt + 3 ≤ ts 4-24
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