che object. (a) At t = 0 seconds, s = 158 feet. At t = 1 second, s = 95 feet. At t = 2 seconds, s = 0 feet. (b) At t = 1 second, s = 136 feet. At t = 2 seconds, s = 88 feet. At t = 3 seconds, s = 8 feet. (c) At t = 1 second, s = 186 feet. At t = 2 seconds, s = 115 feet. At t = 3 seconds, s = 18 feet.
che object. (a) At t = 0 seconds, s = 158 feet. At t = 1 second, s = 95 feet. At t = 2 seconds, s = 0 feet. (b) At t = 1 second, s = 136 feet. At t = 2 seconds, s = 88 feet. At t = 3 seconds, s = 8 feet. (c) At t = 1 second, s = 186 feet. At t = 2 seconds, s = 115 feet. At t = 3 seconds, s = 18 feet.
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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
Transcribed Image Text:An object moving vertically is at the given heights at the specified times. Find the position equation
S 5 = ²1/at² + vot + 50
for the object.
(a) At t = 0 seconds, s = 158 feet.
At t = 1 second, s = 95 feet.
At t = 2 seconds, s = 0 feet.
(b) At t = 1 second, s = 136 feet.
At t = 2 seconds, s = 88 feet.
At t = 3 seconds, s = 8 feet.
(c) At t = 1 second, s = 186 feet.
At t = 2 seconds, s = 115 feet.
At t = 3 seconds, s = 18 feet.
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