CHCR) and C= Let B= - 3 of vis [v]B 1 1 [;)] 3 = A [v] 0 M-[2] 3 ⓇM1.- [³] B [v] = 0 0 4-A] -9 Ⓒ [v]= O O [v]= 4- 23 0 0 3 then what is the coordinate vector [v]? - 3 -2 be bases for R2. If the coordinate vector

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