Chau and Donna are standing on a riverbank, 180 meters apart, at points A and B respectively. (See the figure below.) Donna is 230 meters from a house located across the river at point C. Suppose that angle A (angle BAC) is 49°. What is the measure of angle B (angle AB C)? Round your answer to the nearest tenth of a degree. 180 m 49° 230 m 44 4
Chau and Donna are standing on a riverbank, 180 meters apart, at points A and B respectively. (See the figure below.) Donna is 230 meters from a house located across the river at point C. Suppose that angle A (angle BAC) is 49°. What is the measure of angle B (angle AB C)? Round your answer to the nearest tenth of a degree. 180 m 49° 230 m 44 4
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter8: Applications Of Trigonometry
Section: Chapter Questions
Problem 2T
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What is the measure of
![**Title: Calculating Angles Using the Law of Sines**
**Introduction to the Problem:**
Chau and Donna are standing on a riverbank, 180 meters apart, at points \(A\) and \(B\) respectively. Donna is 230 meters from a house located across the river at point \(C\). Suppose that angle \(A\) (angle \(BAC\)) is \(49^\circ\). What is the measure of angle \(B\) (angle \(ABC\))? Round your answer to the nearest tenth of a degree.
**Diagram Explanation:**
In the provided diagram:
- Points \(A\) and \(B\) are on the riverbank, separated by a distance of 180 meters.
- Point \(C\) represents the location of a house across the river.
- The line segment \(AC\) forms an angle of \(49^\circ\) with line segment \(AB\).
- The distance from point \(B\) to point \(C\) is marked as 230 meters.
- The diagram visually represents the problem with horizontal and vertical lines showing their respective measurements.
**Using the Law of Sines:**
To find the measure of angle \(B\), we can apply the Law of Sines, which states:
\[
\frac{\sin(A)}{a} = \frac{\sin(B)}{b} = \frac{\sin(C)}{c}
\]
Where:
- \(A = 49^\circ\)
- \(a = BC = 230 \text{ meters}\)
- \(b = AC\)
Given that \(AB = 180\) meters, \(A = 49^\circ\), and \(BC = 230\) meters, we can set up the equation as follows to solve for angle \(B\):
\[
\frac{\sin(49^\circ)}{230} = \frac{\sin(B)}{180}
\]
Solving for \(\sin(B)\):
\[
\sin(B) = \frac{180 \times \sin(49^\circ)}{230}
\]
After calculating the right-hand side:
\[
\sin(B) \approx \frac{180 \times 0.7547}{230}
\]
\[
\sin(B) \approx 0.5904
\]
Taking the inverse sine:
\[
B \approx \sin^{-1}(0.590](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4c3dcdda-9290-4eb4-ba73-ee9de7b78657%2F39c7ee80-ee76-4965-b540-f36f2dd49f4c%2Flw46v1p.png&w=3840&q=75)
Transcribed Image Text:**Title: Calculating Angles Using the Law of Sines**
**Introduction to the Problem:**
Chau and Donna are standing on a riverbank, 180 meters apart, at points \(A\) and \(B\) respectively. Donna is 230 meters from a house located across the river at point \(C\). Suppose that angle \(A\) (angle \(BAC\)) is \(49^\circ\). What is the measure of angle \(B\) (angle \(ABC\))? Round your answer to the nearest tenth of a degree.
**Diagram Explanation:**
In the provided diagram:
- Points \(A\) and \(B\) are on the riverbank, separated by a distance of 180 meters.
- Point \(C\) represents the location of a house across the river.
- The line segment \(AC\) forms an angle of \(49^\circ\) with line segment \(AB\).
- The distance from point \(B\) to point \(C\) is marked as 230 meters.
- The diagram visually represents the problem with horizontal and vertical lines showing their respective measurements.
**Using the Law of Sines:**
To find the measure of angle \(B\), we can apply the Law of Sines, which states:
\[
\frac{\sin(A)}{a} = \frac{\sin(B)}{b} = \frac{\sin(C)}{c}
\]
Where:
- \(A = 49^\circ\)
- \(a = BC = 230 \text{ meters}\)
- \(b = AC\)
Given that \(AB = 180\) meters, \(A = 49^\circ\), and \(BC = 230\) meters, we can set up the equation as follows to solve for angle \(B\):
\[
\frac{\sin(49^\circ)}{230} = \frac{\sin(B)}{180}
\]
Solving for \(\sin(B)\):
\[
\sin(B) = \frac{180 \times \sin(49^\circ)}{230}
\]
After calculating the right-hand side:
\[
\sin(B) \approx \frac{180 \times 0.7547}{230}
\]
\[
\sin(B) \approx 0.5904
\]
Taking the inverse sine:
\[
B \approx \sin^{-1}(0.590
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