Chau and Donna are standing on a riverbank, 180 meters apart, at points A and B respectively. (See the figure below.) Donna is 230 meters from a house located across the river at point C. Suppose that angle A (angle BAC) is 49°. What is the measure of angle B (angle AB C)? Round your answer to the nearest tenth of a degree. 180 m 49° 230 m 44 4

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Chapter8: Applications Of Trigonometry
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What is the measure of Angle B? 

**Title: Calculating Angles Using the Law of Sines**

**Introduction to the Problem:**

Chau and Donna are standing on a riverbank, 180 meters apart, at points \(A\) and \(B\) respectively. Donna is 230 meters from a house located across the river at point \(C\). Suppose that angle \(A\) (angle \(BAC\)) is \(49^\circ\). What is the measure of angle \(B\) (angle \(ABC\))? Round your answer to the nearest tenth of a degree.

**Diagram Explanation:**

In the provided diagram:

- Points \(A\) and \(B\) are on the riverbank, separated by a distance of 180 meters.
- Point \(C\) represents the location of a house across the river.
- The line segment \(AC\) forms an angle of \(49^\circ\) with line segment \(AB\).
- The distance from point \(B\) to point \(C\) is marked as 230 meters.
- The diagram visually represents the problem with horizontal and vertical lines showing their respective measurements.

**Using the Law of Sines:**

To find the measure of angle \(B\), we can apply the Law of Sines, which states:

\[
\frac{\sin(A)}{a} = \frac{\sin(B)}{b} = \frac{\sin(C)}{c}
\]

Where:
- \(A = 49^\circ\)
- \(a = BC = 230 \text{ meters}\)
- \(b = AC\)

Given that \(AB = 180\) meters, \(A = 49^\circ\), and \(BC = 230\) meters, we can set up the equation as follows to solve for angle \(B\):

\[
\frac{\sin(49^\circ)}{230} = \frac{\sin(B)}{180}
\]

Solving for \(\sin(B)\):

\[
\sin(B) = \frac{180 \times \sin(49^\circ)}{230}
\]

After calculating the right-hand side:

\[
\sin(B) \approx \frac{180 \times 0.7547}{230}
\]

\[
\sin(B) \approx 0.5904
\]

Taking the inverse sine:

\[
B \approx \sin^{-1}(0.590
Transcribed Image Text:**Title: Calculating Angles Using the Law of Sines** **Introduction to the Problem:** Chau and Donna are standing on a riverbank, 180 meters apart, at points \(A\) and \(B\) respectively. Donna is 230 meters from a house located across the river at point \(C\). Suppose that angle \(A\) (angle \(BAC\)) is \(49^\circ\). What is the measure of angle \(B\) (angle \(ABC\))? Round your answer to the nearest tenth of a degree. **Diagram Explanation:** In the provided diagram: - Points \(A\) and \(B\) are on the riverbank, separated by a distance of 180 meters. - Point \(C\) represents the location of a house across the river. - The line segment \(AC\) forms an angle of \(49^\circ\) with line segment \(AB\). - The distance from point \(B\) to point \(C\) is marked as 230 meters. - The diagram visually represents the problem with horizontal and vertical lines showing their respective measurements. **Using the Law of Sines:** To find the measure of angle \(B\), we can apply the Law of Sines, which states: \[ \frac{\sin(A)}{a} = \frac{\sin(B)}{b} = \frac{\sin(C)}{c} \] Where: - \(A = 49^\circ\) - \(a = BC = 230 \text{ meters}\) - \(b = AC\) Given that \(AB = 180\) meters, \(A = 49^\circ\), and \(BC = 230\) meters, we can set up the equation as follows to solve for angle \(B\): \[ \frac{\sin(49^\circ)}{230} = \frac{\sin(B)}{180} \] Solving for \(\sin(B)\): \[ \sin(B) = \frac{180 \times \sin(49^\circ)}{230} \] After calculating the right-hand side: \[ \sin(B) \approx \frac{180 \times 0.7547}{230} \] \[ \sin(B) \approx 0.5904 \] Taking the inverse sine: \[ B \approx \sin^{-1}(0.590
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