Chart Based Probability Section Rubber Balls in a Box Setup Stripes | Dots Stars Red 8. 15 12 Blue 7 3 14 Green 2 9 6 Experiment: The rubber balls all have the same size, texture, weight, etc. They cannot be distinguished without looking at them. The rubber balls are mixed around thoroughly in the box. One rubber ball is to be drawn randomly. Let X= the color on the rubber ball. Let Y = the pattern on the rubber ball. Use the rubber balls in a box setup. Find P( X = Green OR Y= Stars|). This is a short answered question. The correct answer is a fully simplified fraction.

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Chart Based Probability Section
Rubber Balls in a Box Setup
Stripes | Dots
Stars
Red
8.
15
12
Blue
7
3
14
Green
2
9
6
Experiment: The rubber balls all have the same size, texture, weight, etc. They cannot be
distinguished without looking at them. The rubber balls are mixed around thoroughly in
the box. One rubber ball is to be drawn randomly. Let X= the color on the rubber ball.
Let Y = the pattern on the rubber ball.
Use the rubber balls in a box setup.
Find P( X = Green OR Y= Stars|). This is a short answered question. The correct answer is a
fully simplified fraction.
Transcribed Image Text:Chart Based Probability Section Rubber Balls in a Box Setup Stripes | Dots Stars Red 8. 15 12 Blue 7 3 14 Green 2 9 6 Experiment: The rubber balls all have the same size, texture, weight, etc. They cannot be distinguished without looking at them. The rubber balls are mixed around thoroughly in the box. One rubber ball is to be drawn randomly. Let X= the color on the rubber ball. Let Y = the pattern on the rubber ball. Use the rubber balls in a box setup. Find P( X = Green OR Y= Stars|). This is a short answered question. The correct answer is a fully simplified fraction.
Expert Solution
Step 1

Let A1 be the event that the ball is red,A2 be the event that the ball is blue,A3 be the event that the ball is green.Similarly, let B1 be the event that the ball is stars,B2 be the event that the ball is stripes,B3 be the event that the ball is dots.Then, consider the following table:

  B1 B2 B3 n(Ai)
A1 8 15 12 35
A2 7 3 14 24
A3 2 9 6 17
n(Bj) 17 27 32 76

 

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