Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Question
![**Problem Statement:**
Charles is walking around a fountain that has a circumference of 124 feet. What is the diameter of the fountain?
**Multiple Choice Options:**
- \( \bigcirc \) 7.8 ft
- \( \bigcirc \) 15.5 ft
- \( \bigcirc \) 19.7 ft
- \( \bigcirc \) 39.5 ft
### Explanation:
To solve this problem, we need to use the formula for the circumference of a circle. The formula is:
\[ C = \pi d \]
where \( C \) is the circumference, \( d \) is the diameter, and \( \pi \) (pi) is approximately 3.14159.
### Steps to Solve:
1. Given the circumference (\( C \)) is 124 feet, we can rearrange the formula to solve for the diameter (\( d \)):
\[ d = \frac{C}{\pi} \]
2. Plugging in the given values:
\[ d = \frac{124 \text{ ft}}{3.14159} \approx 39.5 \text{ ft} \]
Therefore, the correct option is:
- \( \bigcirc \) 39.5 ft](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6166de5a-9053-4d84-9ce1-0f690da2cc9c%2Fa651aff0-861c-4972-aa71-3e6b8d5d05f5%2F13uvlnc_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
Charles is walking around a fountain that has a circumference of 124 feet. What is the diameter of the fountain?
**Multiple Choice Options:**
- \( \bigcirc \) 7.8 ft
- \( \bigcirc \) 15.5 ft
- \( \bigcirc \) 19.7 ft
- \( \bigcirc \) 39.5 ft
### Explanation:
To solve this problem, we need to use the formula for the circumference of a circle. The formula is:
\[ C = \pi d \]
where \( C \) is the circumference, \( d \) is the diameter, and \( \pi \) (pi) is approximately 3.14159.
### Steps to Solve:
1. Given the circumference (\( C \)) is 124 feet, we can rearrange the formula to solve for the diameter (\( d \)):
\[ d = \frac{C}{\pi} \]
2. Plugging in the given values:
\[ d = \frac{124 \text{ ft}}{3.14159} \approx 39.5 \text{ ft} \]
Therefore, the correct option is:
- \( \bigcirc \) 39.5 ft
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