Chapter Two: S-domain Circuit Analysis - 2.3 Poles and Zeros of Transfer FunctionsWatch laterShareExample 2.8: Determine the transfer function H(s) = V(s)/I(s) of the circuit in Figure,and then find zeros and poles.Solurion:1,=((s+4)l,)/(s+4+2+1/2s)But V,=21,=(2(s+4)l,)/(s+6+1/25)Hence, H(s)=(V,(s))/0,(5)-(4s(s+4))/(2;?+125+1| Vis)H(s)=2s(s+4)/((s+5.9)(s+0.085))Zeros are: s =0 and s, = -4VIDEOS ire: S1 = -5.9 and s, = -0.085%3D

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Chapter Two: S-domain Circuit Analysis - 2.3 Poles and Zeros of Transfer Functions Watch la Example 2.8: Determine the transfer function H(s) = V(s)/I(s) of the circuit in Fi and then find zeros and poles. Solution: ,=((s+4),)/(s+4+-2+1/2s) But V,=21,=(2(s+4))/(s+6+1/2s) ww Hence, H(s)=(V,(s))/0,(s)=(45(s+4))/(252+12s+1) V(s) 22 H(s)=2s(s+4)/((s+5.9)(s+0.085)) 42 Zeros are: s, 0 and s, = -4 %3D are: s, = -5.9 and s, = -0.085 %3D VIDEOS

Chapter Two: S-domain Circuit Analysis - 2.3 Poles and Zeros of Transfer Functions Watch la Example 2.8: Determine the transfer function H(s) = V(s)/I(s) of the circuit in Fi and then find zeros and poles. Solution: ,=((s+4),)/(s+4+-2+1/2s) But V,=21,=(2(s+4))/(s+6+1/2s) ww Hence, H(s)=(V,(s))/0,(s)=(45(s+4))/(252+12s+1) V(s) 22 H(s)=2s(s+4)/((s+5.9)(s+0.085)) 42 Zeros are: s, 0 and s, = -4 %3D are: s, = -5.9 and s, = -0.085 %3D VIDEOS

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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