Chapter 9 problem 1: Find Zeq at terminals a-b of Circuit 10 using Wye-Delta or Delta-Wye conversions. ασ b rell 2 Ω www j6 Ω ell -j4Ω Η -j6Ω j8 Ω Circuit 10 4Ω j8 Ω j12 Ω

Q: 4 2 j3 2 оа 15/0° A 2Ω 0.51, -j4 2

A: The solution is given below

Q: Va 220/0° V 220-120V 20+30 2 220/120° V Ib Vb 80+/50 2 60-j40 2

A: Step 1: Since, in the question they are not mentionrd the system is balanced or not.....so we can…

Q: Find equivalent impedance of below circuit.

A: It is given that:

Q: Find Z in below figure

A: It is given that:

Q: D Question 9 What is the equivalent impedance between nodes a and b? 3+j3 n 1-j1 n

A: The solution can be achieved as follows.

Q: 6. Use source transformation to find Io.

A:

Q: 1276/45° A I₁ -j20 HE Z e {20 Io 2/0⁰ F₂

A:

Current Division Method

The generalized current divider formula is given by the following relation below,