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Chapter 4: Practices Problems, 7 questions. Name: G# Page 101 Practice Problem 4.1: If the box starts from rest and the worker pulls with a force of 40 N, what is the speed of the box after it has been pulled a distance of 0.36m? Answer: 0.85m/s.

Chapter 4: Practices Problems, 7 questions. Name: G# Page 101 Practice Problem 4.1: If the box starts from rest and the worker pulls with a force of 40 N, what is the speed of the box after it has been pulled a distance of 0.36m? Answer: 0.85m/s.

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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**Chapter 4: Practice Problems, 7 questions** **Name: [Name]** **G#: [G#]** **Page 101 Practice Problem 4.1:** If the box starts from rest, and the worker pulls with a force of 40 N, what is the speed of the box after it has been pulled a distance of 0.36 m? **Answer: 0.85 m/s.**
Transcribed Image Text:**Chapter 4: Practice Problems, 7 questions** **Name: [Name]** **G#: [G#]** **Page 101 Practice Problem 4.1:** If the box starts from rest, and the worker pulls with a force of 40 N, what is the speed of the box after it has been pulled a distance of 0.36 m? **Answer: 0.85 m/s.**
**Example 4.13: A Box on Ice** **Overview:** This example explores a straightforward application of Newton's second law, involving a horizontal force on a box that slides without friction. The aim is to determine the acceleration of the box. **Setup:** - The scenario involves a 40 kg box. - The box is pulled by a worker applying a 20 N horizontal force. - Friction is absent, implying that no force opposes the motion. **Objective:** - Calculate the acceleration of the box. **Solution Steps:** 1. **Force Balance:** - The horizontal component of the force, \( \Sigma F_x \), is calculated by \( \Sigma F_x \) = 20 N. - The acceleration, \( a \), is given by \( a = \frac{F}{m} = \frac{20 \, \text{N}}{40 \, \text{kg}} = 0.5 \, \text{m/s}^2 \). 2. **Vertical Forces:** - In the vertical direction, the forces include gravitational pull and the normal force by the ice. - The net force vertically is zero because there is no vertical acceleration. 3. **Practice Problem:** - If the box starts from rest and is pulled 0.35 m, calculate the speed. - Solution: \( v = 0.88 \, \text{m/s} \). **Diagram Explanation:** - **Figure 4.13:** - Illustrates a worker pulling a box across a flat surface. - Horizontal arrow indicates the 20 N force applied. - Vertical arrows show forces: gravitational pull downwards and normal force upwards. This problem exemplifies the basic principles of Newton's laws in a frictionless setting, highlighting the relation between force, mass, and acceleration. **Reflection:** Understanding that the box is subject only to horizontal acceleration emphasizes the direct relationship between force and acceleration when friction is negligible.
Transcribed Image Text:**Example 4.13: A Box on Ice** **Overview:** This example explores a straightforward application of Newton's second law, involving a horizontal force on a box that slides without friction. The aim is to determine the acceleration of the box. **Setup:** - The scenario involves a 40 kg box. - The box is pulled by a worker applying a 20 N horizontal force. - Friction is absent, implying that no force opposes the motion. **Objective:** - Calculate the acceleration of the box. **Solution Steps:** 1. **Force Balance:** - The horizontal component of the force, \( \Sigma F_x \), is calculated by \( \Sigma F_x \) = 20 N. - The acceleration, \( a \), is given by \( a = \frac{F}{m} = \frac{20 \, \text{N}}{40 \, \text{kg}} = 0.5 \, \text{m/s}^2 \). 2. **Vertical Forces:** - In the vertical direction, the forces include gravitational pull and the normal force by the ice. - The net force vertically is zero because there is no vertical acceleration. 3. **Practice Problem:** - If the box starts from rest and is pulled 0.35 m, calculate the speed. - Solution: \( v = 0.88 \, \text{m/s} \). **Diagram Explanation:** - **Figure 4.13:** - Illustrates a worker pulling a box across a flat surface. - Horizontal arrow indicates the 20 N force applied. - Vertical arrows show forces: gravitational pull downwards and normal force upwards. This problem exemplifies the basic principles of Newton's laws in a frictionless setting, highlighting the relation between force, mass, and acceleration. **Reflection:** Understanding that the box is subject only to horizontal acceleration emphasizes the direct relationship between force and acceleration when friction is negligible.
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