Chapter 4 Newton's Laws of Motion Exercise 4.11 - Enhanced - with Solution 3 of 10 A hockey puck with mass 0.160 kg is at rest at the origin (x-0) on the horizontal, fnictionless surface of the rink. At time t= 0 a player applies a force of 0 250 N to the puck, parallel to the x-axis, he continues to apply this force until t= 2,00 s. Previous Answers Constants V Correct You may want to review (Pages 108 -113), Correct answer is shown. Your answer required for this part. 21.86 m was either rounded differently or used a different number of significant figures than For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Determining acceleration from force In the time interval from t = 5.00 s to 7.00 s the acceleration is again a,=1.562 m/s At the start of this interval voz = 3.12 m/s and Io = 12.5 m. %3D r – Lo = Vozt + a,ť = (3.12 m/s)(2.00 s) +(1.562 m/s²)(2.00 s)² I – T, = 6.24 m +3.12 m=9.36 m Therefore, at t=7.00 s the puck is at z = To +9.36 m= 12.5 m +9.36 m=21.9 m Part D In this case what is the speed of the puck? ΠΑΣΨ m/s Request Answer Previous AnSwers Submit P Pearson Privacy Policy | Permissions | Contact Us Terms of Use 5:25 PM Copyright © 2020 Pearson Education Inc. All rights reserved. 215/2020 to search

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Distance and Speed

The speed, distance and time relation forms the basis of study of motion. You will need these concepts in the study of Mechanics. This concept is applicable for students who are studying the following courses –