Chapter 14, Problem 031 A block of wood floats in fresh water with 0.675 of its volume V submerged and in oil with 0.871 V submerged. Find the density of (a) the wood and (b) the oil. Units (a) Number (b) Number Units
Chapter 14, Problem 031 A block of wood floats in fresh water with 0.675 of its volume V submerged and in oil with 0.871 V submerged. Find the density of (a) the wood and (b) the oil. Units (a) Number (b) Number Units
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Question
![Chapter 14, Problem 031
A block of wood floats in fresh water with 0.675 of its volume V submerged and in oil with 0.871 V submerged. Find the density of (a) the wood and (b) the oil.
Units
(a) Number
(b) Number
Units](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F38f36218-c367-4ade-b1eb-478c767b3001%2Ff8141fa0-ad1d-46d9-806e-ea2696314a80%2Fmnb68lc.png&w=3840&q=75)
Transcribed Image Text:Chapter 14, Problem 031
A block of wood floats in fresh water with 0.675 of its volume V submerged and in oil with 0.871 V submerged. Find the density of (a) the wood and (b) the oil.
Units
(a) Number
(b) Number
Units
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
Step 1
a)
As wooden block floats on water, buoyant force exerted by water on block will be equal to the weight of block acting downwards.
![moP(0.675Vk)
Psioc Vliock =(0.675)P,Vsedk
Petoeck =(0.675)P
(0.675)(1000kg/m2)
675kg/m3
block](https://content.bartleby.com/qna-images/answer/38f36218-c367-4ade-b1eb-478c767b3001/292ae6f3-1895-4c83-b590-1354d03ae016/mltujv.png)
Step 2
Answer: 675 kg/m3
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