Chapman 3.4 3-4. A single-phase power system is shown in Figure P3-1. The power source feeds a 100-kVA 14/2.4-kV transformer through a feeder impedance of 38.2 +j140 2. The transformer's equivalent series impedance referred to its low-voltage side is 0.12 + j0.5 22. The load on the transformer is 90 kW at 0.85 PF lagging and 2300 V. 1402 V₁ semen Source 38.20 WWW Feeder (transmission line) 3120 josn WWW Trangtomer (a) What is the voltage at the power source of the system? (b) What is the voltage regulation of the transformer? (c) How efficient is the overall power system? Load Load 90 kw 0.85 PF logging

Chapman 3.4 3-4. A single-phase power system is shown in Figure P3-1. The power source feeds a 100-kVA 14/2.4-kV transformer through a feeder impedance of 38.2 +j140 2. The transformer's equivalent series impedance referred to its low-voltage side is 0.12 + j0.5 22. The load on the transformer is 90 kW at 0.85 PF lagging and 2300 V. 1402 V₁ semen Source 38.20 WWW Feeder (transmission line) 3120 josn WWW Trangtomer (a) What is the voltage at the power source of the system? (b) What is the voltage regulation of the transformer? (c) How efficient is the overall power system? Load Load 90 kw 0.85 PF logging

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Similar questions

In single phase transformer, if the secondary turns N2 is greater than the primary turns N1, then what is the relation between V2 and V1? O a. V2 = V1 O b. V2 > V1 O c. V1 < V2 O d. V2 < V1
Solve it quickly please
Which of the following is the correct equation for calculating the rated current for a single-phase transformer? A. I=va/e b.I=sc/e c.a/e d.e×z/e
In no load phasor diagram of practical transformer, the magnetizing current Imag is with flux Ø O Leading by 30° O Lagging by 60° In phase O 90° out of phase
925 3- The approximate equivalent circut of is to be determined. The open-circuit at 0 20KVA, 8000/240 V 60 Hz transformar short-circut tests that were performed transformer. primary side gave the following results. Open - Circut Test V₁x = 8000 Iloc=0-214 A Ploc = 400 W Short-Circuit Test |Visc = 489V 5₁s = 2.5A Pisc = 240k/ al Find the components of the magnetising branch i referred to the primary side b) Find the Components of the equivalent series impedence referred to the primary side. 119 210 2 15 16
TYDDIAD I Q4-(A)-draw the phasor diagram of the transformer at full load with inductive load
Which of the following statements is true about an ideal transformer? O It changes the magnitude of DC signals. O It converts DC signals into AC signals. O It converts AC signals into DC signals. O It changes the magnitude of AC signals. hp
Q4 Figure Q4 below shows the simplified per phase equivalent circuit of a 220 V star connected transformer. The parameters for the equivalent circuit is listed as follows: R1= 1.780 Ohm, R2 = 2.400 Ohm, Re = 0 Xi = 1.255 Ohm, X2 = 0.410 Ohm, XM = 15.000 Ohm Stray loss = 200 W, Core loss = 100 W RI jXi I2 jX2 IM Rc jXm R2 Figure Q4 (a) Find the line current of the transformer. Find the copper loss associated with the primary winding and secondary winding. (b) (c) Calculate the efficiency of the 3 phase transformer.