please answer the question given Part 2 – Open Channel Flow and Translatory WavesChannel width = 7.7_cmFlow, Q =1.0 liters/secAvg.Calc.TimeTheoret.Vwy1y1y2y2Avg.Meas.y1y2V1Vw(ст) | (ст)(cm/sec) (cm) | (sec)(cm/sec)(cm/sec))(cm) (cm)(cm)(cm)3.654.206.606.454007.94% Difference between measured and theoretical:Calculations:

Channel width = 7.7_cm Flow, Q =1.0 liters/sec Avg. Calc. V, Time Meas. Vw y1 y1 Avg. y2 y2 Theoret. y1 y2 Vw (cm) (cm) (cm) | (cm) (cm) (cm) | (cm/sec) (cm) | (sec) (cm/ sec) (cm/ sec)) 3.65 4.20 6.60 6.45 400 7.94 % Difference between measured and theoretical:

Channel width = 7.7_cm Flow, Q =1.0 liters/sec Avg. Calc. V, Time Meas. Vw y1 y1 Avg. y2 y2 Theoret. y1 y2 Vw (cm) (cm) (cm) | (cm) (cm) (cm) | (cm/sec) (cm) | (sec) (cm/ sec) (cm/ sec)) 3.65 4.20 6.60 6.45 400 7.94 % Difference between measured and theoretical:

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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please answer the question given

Part 2 – Open Channel Flow and Translatory Waves
Channel width = 7.7_cm
Flow, Q =1.0 liters/sec
Avg.
Calc.
Time
Theoret.
Vw
y1
y1
y2
y2
Avg.
Meas.
y1
y2
V1
Vw
(ст) | (ст)
(cm/sec) (cm) | (sec)
(cm/
sec)
(cm/
sec))
(cm) (cm)
(cm)
(cm)
3.65
4.20
6.60
6.45
400
7.94
% Difference between measured and theoretical:
Calculations:

Expert Solution

Step 1

Measured Velocity of flow.

The length of measured flow is L=400 cm.

The time of measured flow is T=7.94 sec.

The measured velocity of the flow is V_m

$\begin{array}{rcl} V_{m} & = & \frac{L}{T} \\ = & \frac{(400 cm)}{(7.94 sec)} \\ = & 50.378 cm/sec \end{array}$

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