Channel sections are used as a purlin. The top chords of the truss are sloped at 6H to 1V. Trusses are spaced 4m on centers. Use the properties of the channel section in the picture. Loads: Dead load = 600 Pa Live load = 800 Pa Wind load = 1,300Pa Wind coefficients: Windward = 0.25 Leeward = -0.4 Use Fbx=Fby=248 MPa. Determine the safe spacing of purlins (Use load combination of 0.75(D+L+W)

Q: Please show clear and complete solutions. Box the final answers. Note: The tolerance is ± 1 in the…

A: The truss with the loading and support conditions is given as To find:- Force in members BG and BF

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Q: Current Attempt in Progress Determine the force in each member of the loaded truss. All triangles…

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Q: Determine the force in member BE of the loaded truss. The force is positive if in tension, negative…

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Q: < 250 mm A D P = 25 kN B 30 60 C TOP VIEW 280 mm Member AD is fabricated by joining two bars…

A: E=2G(1+μ)μ=E2G-1 GIVEN E=205GPa G=82GPa NOW USING ABOVE FORMULA μ=2052x82-1 μ=.25

Q: Problem # 3: The strut AB made from two bars (thickness of each bar = 0.50 in) is connected to a…

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Q: Channel sections are used as a purlin. The top chords of the truss are sloped at 5H to 2V. Trusses…

A: Given, DL= 750 Pa LL= 1000 Pa WL=1400 Pa Spacing of purlin=1.4 m Spacing of truss=l= 5m Slope= 5H:2V…

Q: DF, CE and BD.

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Q: Determine force in member AB

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Q: 1. A rectangular beam has uniformly distributed dead and live loads along its full length as shown…

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Q: Zero Force Members B Identify the Zero Force Members in the Truss Structure below. C DEFG P N WA N M…

A: A truss is loaded as follows

Q: The beam, W410 mm x 67 kg/m, with 9mm web thickness subjects the girder, W530 mm x 109 kg/m with 12…

A: Bolt shear stress, Fv = 120 MPaBolt bearing stress, Fp = 480 MPaweb thickness, t = 9 mmTo find:The…

Q: Determine the required tension steel area for d' = 75mm b = 350mm d = 470mm fc' = 30MPa fy = 400 MPa

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Methods to Determine Vertical Stress

The load applied to the soil is transferred to the underground. The presence of water at soil pores and solid grains above the soil are the primary components that are responsible for the effective load transfer. Due to the load acting, the internal component of the soil or the underground formations undergoes deformations or a tectonic shift. The amount of deformation depends upon the amount of load acting on the soil surface, which indeed, depends on the weight of everything present above the soil. Due to this, the underground soil element develops internal stresses which try to resist the tectonic changes.