changes llocated alloy Juring age Thardening. You should use a sketch the microstructure of your material (i) held for 30 I minutes at the solution temperature, (i) after, subsequently, cooling rapidly from the I solution temperature to room temperature, (i) after, subsequently, holding at the commercial aging temperature for the prescribed time, to support your explanation. b) Compare and contrast how precipitates (i) increase the yield strength of some.alloys. at room temperature, and (i) lower the creep rate of some alloys at elevated temperature. c) Your allocated alloy is strengthened by intermetallic precipitates that grow during aging. By both defining an intermetallic and detailing those found in your alloy, explain

changes llocated alloy Juring age Thardening. You should use a sketch the microstructure of your material (i) held for 30 I minutes at the solution temperature, (i) after, subsequently, cooling rapidly from the I solution temperature to room temperature, (i) after, subsequently, holding at the commercial aging temperature for the prescribed time, to support your explanation. b) Compare and contrast how precipitates (i) increase the yield strength of some.alloys. at room temperature, and (i) lower the creep rate of some alloys at elevated temperature. c) Your allocated alloy is strengthened by intermetallic precipitates that grow during aging. By both defining an intermetallic and detailing those found in your alloy, explain

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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(a) Briefly describe at least five methods to increase the strength of materials. (b) What are the metallurgical/processing techniques employed to enhance the creep resistance of metal alloys? (c) Cite three variables that determine the microstructure of an alloy. (d) What are the most common types of crystal defects and how do they affect properties? (e) Briefly describe the phenomenon of coring and why it occurs.
Using the isothermal transformation diagram for a 0.45 wt% C steel alloy (Animated Figure 10.40), determine the approximate percentages of the microconstituents that form the final microstructure of a small specimen that has been subjected to the following time- temperature treatments. In each case assume that the specimen begins at 845°C (1550°F), and that it has been held at this temperature long enough to have achieved a complete and homogeneous austenitic structure.
Please draw each scenario using the TTT diagram
Instead of creating one, just draw the model on paper, be specific and show work! This is for materials of engineering class!
please draw each question on the TTT diagram
Below is a continuous cooling transformation curve for steel (upper) and for a silicate melt (lower). Describe the similarities and differences as follows. a. What is the critical cooling rate in each case? b. What phase(s) form in each case when the critical cooling rate is exceeded? c. What phase(s) form in each case if the cooling rate is very slow? 800 1400 Ae lemperature Austenite *peorlite begins 10FI 700 1200 Austenitepearlite complete 1600 1000 5009 800 Tronsformation stops 400 600 300 400 Austenite -mortenstic structure 200 -Isathermal dogram Continuous transformaton diogrom Constant rate coding curves - 100 200 Findl structure Mortensite Morlensite i peorlile Peorite (softer, coorser- 0.1 10? 10 Tronsformation time, seconds Continuous Cooling-Transformation (C-T)Diagram (Derived from the isothermal-transformation diagram for a plain-carbon eutectoid steel) 1200 Glass Crystallization begins 1100 1000 Critical cooling rate Glass-ceramic 900 Crystallization ends 800 700 102 10…
During 650°C, the average grain diameter of a brass material was measured as a function of time, as seen below at two distinct points of Time (min) Grain Diameter (mm) 30 3.9 × 10^-2 90 6.6 × 10^-2 a. What was the grain diameter at the start? (orig diameter) b. What is the expected grain diameter after 150 minutes at 650 °C?
Use the following TTT Diagram for the following questions: 800 A 1400 -Eutectoid temperature 700 1200 600 1000 500 800 400 600 300 Mistart) 200 50% 400 M+A M(50%) M(90%) 100 200 10-1 10 102 103 10 105 Time (s) Temperature ("C) Termperature (°F)
Using the isothermal transformation diagram for a 0.45 wt% C steel alloy (Animated Figure 10.40), determine the approximate percentages of the microconstituents that form the final microstructure of a small specimen that has been subjected to the following time– temperature treatments. In each case assume that the specimen begins at 845°C (1550°F), and that it has been held at this temperature long enough to have achieved a complete and homogeneous austenitic structure.
(v) The two sketches below represent the microstructure of two specimens with identical average composition but subjected to different annealing treatments. a A is stronger and more ductile than B, b. B is stronger and more ductile than A, A is stronger but more brittle than B, B is stronger but more brittle than A, e. none of the above. c. d. A B
Using the isothermal transformation diagram for a 1.13 wt% C steel alloy, determine the final microstructure (in terms of the microconstituents present) of a small specimen that has undergone the following time-temperature treatments. In each case suppose that the sample begins at 920 ° C and that it has been held at this temperature for the timesufficient to achieve a complete and homogeneous austenitic structure. (a) Quickly cool to 250 ° C, hold for 103 s, then cool to room temperature.(b) Quickly cool to 400 ° C, hold for 500 s, then cool to room temperature.(c) Quick cool to 700 ° C, hold for 105 s, then cool to room temperature.(d) Rapidly cool to 650 ° C, hold for 3 s and rapidly cool to 400 ° C, hold that temperature for 25 s and cool to room temperature.(e) Quick cool to 650 ° C, hold for 7 s, then cool to room temperature.
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