Change the Cartesian integral to an equivalent polar integral, and then evaluate. 1 dy dx - 5 25-x2 1+x n(5 + In 6) O A. 2 n(5 - In 6) O B. 2 n(5 - In 6) OC. 4 n(5 + In 6) OD. 4

Calculus: Early Transcendentals
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Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Question:**

Change the Cartesian integral to an equivalent polar integral, and then evaluate.

\[
\int_{-5}^{5} \int_{-\sqrt{25-x^2}}^{\sqrt{25-x^2}} \frac{1}{1+\sqrt{x^2+y^2}} \, dy \, dx
\]

**Options:**

- A. \(\frac{\pi(5 + \ln 6)}{2}\)

- B. \(\frac{\pi(5 - \ln 6)}{2}\)

- C. \(\frac{\pi(5 - \ln 6)}{4}\)

- D. \(\frac{\pi(5 + \ln 6)}{4}\)
Transcribed Image Text:**Question:** Change the Cartesian integral to an equivalent polar integral, and then evaluate. \[ \int_{-5}^{5} \int_{-\sqrt{25-x^2}}^{\sqrt{25-x^2}} \frac{1}{1+\sqrt{x^2+y^2}} \, dy \, dx \] **Options:** - A. \(\frac{\pi(5 + \ln 6)}{2}\) - B. \(\frac{\pi(5 - \ln 6)}{2}\) - C. \(\frac{\pi(5 - \ln 6)}{4}\) - D. \(\frac{\pi(5 + \ln 6)}{4}\)
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