CHALLENGE ACTIVITY 6.9.1: Function errors: Copying one function to create another. Using the celsius_to_kelvin function as a guide, create a new function, changing the name to kelvin_to_celsius, and modifying the function accordingly. Sample output with input: 283.15 10.0 C is 283.15 K 283.15 K is 10.0 C Use python please.
CHALLENGE ACTIVITY 6.9.1: Function errors: Copying one function to create another. Using the celsius_to_kelvin function as a guide, create a new function, changing the name to kelvin_to_celsius, and modifying the function accordingly. Sample output with input: 283.15 10.0 C is 283.15 K 283.15 K is 10.0 C Use python please.
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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CHALLENGE ACTIVITY
6.9.1: Function errors: Copying one function to create another.
Using the celsius_to_kelvin function as a guide, create a new function, changing the name to kelvin_to_celsius, and modifying the function accordingly.
Sample output with input: 283.15
Sample output with input: 283.15
10.0 C is 283.15 K
283.15 K is 10.0 C
Use python please.
![344614.2153518.qx3zqy7
1 def celsius_to_kelvin(value_celsius):
value_kelvin = 0.0
1 test
2
passed
3
value_kelvin = value_celsius + 273.15
return value_kelvin
4
5
All tests
6
passed
7' Your solution goes here '
8
9 value_c = 10.0
10 print(value_c, 'C is', celsius_to_kelvin(value_c), 'K')
11
12 value_k = float(input())
13 print(value_k, 'K is', kelvin_to_celsius (value_k), 'C')
Run](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fdaa61bc1-e8a7-459a-a128-5e7dc4d15081%2F83dadad8-958c-4cd9-85fe-a52ed0a3f4aa%2Focc3rvf_processed.png&w=3840&q=75)
Transcribed Image Text:344614.2153518.qx3zqy7
1 def celsius_to_kelvin(value_celsius):
value_kelvin = 0.0
1 test
2
passed
3
value_kelvin = value_celsius + 273.15
return value_kelvin
4
5
All tests
6
passed
7' Your solution goes here '
8
9 value_c = 10.0
10 print(value_c, 'C is', celsius_to_kelvin(value_c), 'K')
11
12 value_k = float(input())
13 print(value_k, 'K is', kelvin_to_celsius (value_k), 'C')
Run
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