Challenge problem IR peaks: 2966 (very broad), 1721, 780 cm¹. The signal at 12.8 ppm disappears with the addition of D₂O. Hint: The signal at 3.8 ppm is bound to the functional group represented by the signal at 12.8 ppm. Chemical Formula: C13H1802 1H, broad singlet 12 10 d = doublet 2H, d -0 8 2H, d PPM 6 2H, d 1H, quartet 6H, d 3H, d 1H, m 2
Challenge problem IR peaks: 2966 (very broad), 1721, 780 cm¹. The signal at 12.8 ppm disappears with the addition of D₂O. Hint: The signal at 3.8 ppm is bound to the functional group represented by the signal at 12.8 ppm. Chemical Formula: C13H1802 1H, broad singlet 12 10 d = doublet 2H, d -0 8 2H, d PPM 6 2H, d 1H, quartet 6H, d 3H, d 1H, m 2
Chemistry
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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You complete the following problems by drawing the structure of the compound associated with the proton NMR spectra provided

Transcribed Image Text:Challenge problem
IR peaks: 2966 (very broad), 1721, 780 cm¹. The signal at 12.8 ppm disappears with the addition of D₂O.
Hint: The signal at 3.8 ppm is bound to the functional group represented by the signal at 12.8 ppm.
Chemical Formula: C13H1802₂
1H, broad singlet
12
10
d = doublet
2H, d 2H, d
-8
PPM
6
NO
HS
ser alumise
1H, quartet
4
Jeidlich HS
2H, d
6H, d
3H, d
1H, m
2
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