Challenge: Hesse's law can be very useful. It can be used to measure enthalpies for reactions that don't take place, and thus don't exist. The following reaction does not exist 3,3-oxybis-Propanenitrile (CçH3N2O (g)) → 4,6-Dimethyl-2-pyrimidone (C6H&N2O (g)) NH What is the enthalpy of the reaction above if the energetics of the following formation reactions are known: 6C(s) + 4H2(g) + 1/2O2(g) + N2(g) → C,H§N2O (g)(propanenitrile) 6C(s) + 4H2(g) + 1/2O2(g) + N2(g) → C,H3N2O (g)(pyrimidone) A¢H° = -83 kJ/mole A¢H° = -254 kJ/mole

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Challenge:
Hesse's law can be very useful. It can be used to measure enthalpies for reactions that don't take
place, and thus don't exist. The following reaction does not exist
3,3-oxybis-Propanenitrile (CçH3N2O (g)) → 4,6-Dimethyl-2-pyrimidone (C6H&N2O (g))
NH
What is the enthalpy of the reaction above if the energetics of the following formation reactions
are known:
6C(s) + 4H2(g) + 1/2O2(g) + N2(g) → C,H§N2O (g)(propanenitrile)
6C(s) + 4H2(g) + 1/2O2(g) + N2(g) → C,H3N2O (g)(pyrimidone)
A¢H° = -83 kJ/mole
A¢H° = -254 kJ/mole
Transcribed Image Text:Challenge: Hesse's law can be very useful. It can be used to measure enthalpies for reactions that don't take place, and thus don't exist. The following reaction does not exist 3,3-oxybis-Propanenitrile (CçH3N2O (g)) → 4,6-Dimethyl-2-pyrimidone (C6H&N2O (g)) NH What is the enthalpy of the reaction above if the energetics of the following formation reactions are known: 6C(s) + 4H2(g) + 1/2O2(g) + N2(g) → C,H§N2O (g)(propanenitrile) 6C(s) + 4H2(g) + 1/2O2(g) + N2(g) → C,H3N2O (g)(pyrimidone) A¢H° = -83 kJ/mole A¢H° = -254 kJ/mole
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