CHALLENGE 4.3.3: While loop: Insect growth. ACTIVITY Given positive integer numinsects, write a while loop that prints, then doubles, numinsects each iteration. Print values < 100. Follow each number with a space. After the loop, print a newline. Ex: If numInsects = 8, print: 8 16 32 64 Learn how our autograder works 480676.1279990.qx3zqy7 1 #include 2 3 int main(void) { 4 5 6 7 8 9 10 11 } Run int numInsects; scanf("%d", &numInsects); // Must be >= 1 /* Your solution goes here */ return 0; 1 test passed All tests

CHALLENGE 4.3.3: While loop: Insect growth. ACTIVITY Given positive integer numinsects, write a while loop that prints, then doubles, numinsects each iteration. Print values < 100. Follow each number with a space. After the loop, print a newline. Ex: If numInsects = 8, print: 8 16 32 64 Learn how our autograder works 480676.1279990.qx3zqy7 1 #include 2 3 int main(void) { 4 5 6 7 8 9 10 11 } Run int numInsects; scanf("%d", &numInsects); // Must be >= 1 /* Your solution goes here */ return 0; 1 test passed All tests

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Q1: Telling in detail what is the "for" loop doing, how it works, and what is the last statement doing? Q2: How do you know it break down the loop? which one is control it? Telling the detail. Q3: It is direct access. you do not move from beginning. Give me the code. Q4; Which direction to move and from which side to starting? Write a set of Java Code for it, too. Q5: Write a set of code, too.
Gradient FillIn this labwork are asked to write a GUI application again using AWT. This is a fairly easy labworkthat is more about getting used to synchronized online learning. You are expected to:• Draw two rectangles.• Both of them should be filled using GradientPaint() function of AWT. (Check out itsfunction definition that is listed below.)• The first gradient should be parallel to the diagonal of the first rectangle. The colorgradient should not be repeated (acyclic).• The second gradient should be horizontal. The color gradient should be repeated forthis one (cyclic).• You are free to choose the colors but other than that your output should be similar tothe example screenshot given below.
Writepseudocodethatperformsthefollowing:Askausertoenteranumber.Ifthe number is between 0 and 10, write the word blue. If the number is between 10 and 20, write the word red. if the number is between 20 and 30, write the word green. If it is any other number, write that it is not a correct color option.
Write a code using Console.WriteLine for the image.
JavaScript imageMosaic: compute image mosaic. You must implement the final version of the image mosaic algorithm we discussed in class (which includes the scaling of mosaic images and also randomization). Since the algorithm involves several nested loops and can take a while to run, this function will be implemented using a non-blocking loop so that the browser will not complain about its running speed. Details are in the comments embedded in the code. function imageMosaic(input, output, mosaic_name) { let width = input.width; let height = input.height; let mimages = mosaics[mosaic_name]; // mimages is an array of mosaic images let w = mimages[0].width; // all mosaic images have the same size wxh let h = mimages[0].height; let num = mimages.length; // number of mosaic images console.log('Computing Image Mosaic...'); let y = 0; (function chunk() { for(x = 0; x <= width-w; x += w) { // x loop // ===YOUR CODE STARTS HERE=== /* for(y=0; y<=input.height-h; y+=h) { for (x=0;…
1. The main function creates 5 pixels with random red, green, and blue values. Complete the id_color function to return “red" if the red value is greater than the green and blue, "green" if the green value is greater than the red and blue, and “blue" if the blue value is greater than the red and green. If there is no clear maximum value (for example, if the red and green values are the same) return None. Do not change the main function. Save & Run 10/22/2020, 3:44:29 PM - 4 of 4 Show in CodeLens 1 import image 2 import random 4 def id_color(p): '''Returns the dominant color of pixel p''' pass #Your code here to determine the dominant color and return a string identif #Hint: get the red, green & blue values and use an if statement to determine wh 7 8. 9. 10 def main(): '''Controls the program' for i in range(5): 11 12 #Loop 5 times
Assignment4B: Diamonds in the sky. In our earliest labs, we asked you to print a diamond pattern to the screen using predefined print statements. Now that we know how to use loops, we can make more dynamic and customizable patterns. For this assignment, we will prompt the user to enter a maximum width for the diamond. If they enter a number less than 3, we'll prompt them to choose a correct width. If they enter an even number (greater than 3), we will add 1 to it and let the user know the final diamond size. Then we will generate and print out the diamond using * and '' symbols. Hints: Each line of the "diamond" is made up of two parts – the asterisks in the center and the spaces to the left of it. The amount of "left space" decreases as we go towards the middle diamond, then increases afterwards as we go towards the bottom. Could we use multiple loops (or even nested loops) to model this behavior? Also, note that the number of asterisks increases (and later decreases) by two on each…
Test.py ## test# 3 * 3 grid : boardgrid = [' *','* ','*','*','*','*','*','*','*'] # we have two players denomted as "X" and "O" play=Truecount=0 while play:# add first playeradd_x=True# loop to add playerwhile add_x:# at which postion you would like to add the playerplayer_postion_x=int(input ("Enter postion for player X: "))## add X player into the boardif grid[player_postion_x-1]!="X" and grid[player_postion_x-1]!="O":grid[player_postion_x-1]="X"add_x=False#to count the number of added playerscount=count+1else:print ("The postion has been taken")if grid[0]=="X" and grid[1]=="X" and grid[2]=="X":print ("Player X win")print(grid[0:3])print(grid[3:6])print(grid[6:9])breakelif grid[3]=="X" and grid[4]=="X" and grid[5]=="X":print ("Player X win")print(grid[0:3])print(grid[3:6])print(grid[6:9])breakelif grid[6]=="X" and grid[7]=="X" and grid[7]=="X":print ("Player X win")print(grid[0:3])print(grid[3:6])print(grid[6:9])breakelif grid[0]=="X" and grid[3]=="X" and grid[6]=="X":print…
Q.Create an interesting educational information chat box that asks the user to give an input question and then answers the question given by user with a suitable answer. You can make use of list for different questions and answers.Save two to three answers for a single question and then for random selection of elements from those answers use random choice(list) method from random module that returns a random element. Also for a user question that doesn't matches with the questions present in the chat box it should display statement like "oops i can't answer that" "sorry i am not intelligent enough" "could u please ask something else" using random method so that every time one of these statements appear **coding language python ***try using basic programming techniques in python without using arrays and pointers * * * copy paste the program itself and also the screenshot of program and output * * * use any type of data for questions such as name details of cities species etc depends on…
Tic Tac Toe Game from HTML It Needs to countdown from 1 minutes and there will be only 8 possible ways to win.For X&O's you can use images. -User vs computer-Computer plays randomly(location of X's)-if timer reaches to 0 before all 9 spaces filled computer wins.-Computer always starts first and always plays with X.
1. In the first loop, the low number will be the starting point for the loop and thehigh will be the ending point. The loop should display the iterator number andthat number x 10 on the same line, separated by a tab. See example on p. 177.2. The second loop should accumulate all the numbers between the starting pointand ending point. You will need to create and initialize an accumulator such astotal before you start the loop.
I don't need the get_new_item and the color of the items but it breaks the code, how do I fix this? WEIGHT_LIMIT = 100COUNT_LIMIT = 4wizard_inventory = [] def display_title(): print("The Wizard Inventory program") print() def display_menu(): print("COMMAND MENU") print("show - Show all items") print("grab - Grab an item") print("edit - Edit an item") print("drop - Drop an item") print("exit - Exit program") print() def show(inventory): print("Show inventory") for i in inventory: print(i[0], i[1], "(", i[2], ")lbs") total = calculate_weight(inventory) print("Total Weights is : ", total, "lbs") print(" Weight limits of 100 lbs") def calculate_weight(inventory): total = 0 for i in inventory: print(i[2]) total = total + float(i[2]) return totaldef grab_item(inventory): list = [] total = 0 if (len(inventory) < 4): list.extend(get_new_item()) print(list) total =…