CHALLENGE 3.17.1: Conditional expression: Print negative or positive. ACTIVITY Create a conditional expression that evaluates to string "negative" if userVal is less than 0, and "non-negative" otherwise. Ex: If userVal is -9, output is: -9 is negative 1 #include 2 #include 1 test 3 using namespace std; passed 4 5 int main ) { string condStr; int userVal; 6 All tests 7 passed 8 cin userVal; 9 10 /* Your solution goes here */; condStr 11 12
CHALLENGE 3.17.1: Conditional expression: Print negative or positive. ACTIVITY Create a conditional expression that evaluates to string "negative" if userVal is less than 0, and "non-negative" otherwise. Ex: If userVal is -9, output is: -9 is negative 1 #include 2 #include 1 test 3 using namespace std; passed 4 5 int main ) { string condStr; int userVal; 6 All tests 7 passed 8 cin userVal; 9 10 /* Your solution goes here */; condStr 11 12
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Question
![CHALLENGE
3.17.1: Conditional expression: Print negative or positive.
ACTIVITY
Create a conditional expression that evaluates to string "negative" if userVal is less than 0, and "non-negative" otherwise. Ex: If
userVal is -9, output is:
-9 is negative
1 #include <iostream>
2 #include <string>
1 test
3 using namespace std;
passed
4
5 int main ) {
string condStr;
int userVal;
6
All tests
7
passed
8
cin userVal;
9
10
/* Your solution goes here */;
condStr
11
12
<condStr << "." « endl;
cout << userVal << " is '
13
14
return 0;
15
16
Run
DD](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4623cf4b-f6e9-4aaf-a899-cb2d5a830b47%2F91dfdf0f-21cb-4151-9665-0ff9ee1d329c%2Fwdj4dt2.png&w=3840&q=75)
Transcribed Image Text:CHALLENGE
3.17.1: Conditional expression: Print negative or positive.
ACTIVITY
Create a conditional expression that evaluates to string "negative" if userVal is less than 0, and "non-negative" otherwise. Ex: If
userVal is -9, output is:
-9 is negative
1 #include <iostream>
2 #include <string>
1 test
3 using namespace std;
passed
4
5 int main ) {
string condStr;
int userVal;
6
All tests
7
passed
8
cin userVal;
9
10
/* Your solution goes here */;
condStr
11
12
<condStr << "." « endl;
cout << userVal << " is '
13
14
return 0;
15
16
Run
DD
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