CHALLENGE 3.16.2: Conditional expression: Print negative or positive. ACTIVITY Create a conditional expression that evaluates to string "negative" if userval is less than 0, and "non-negative" otherwise. Ex If userval is-9, output is: -9 is negative. Replace the code comment/* Your solution goes here */ with your solution. The rest of the code, including the parentheses and semicolon, cannot be edited. Learn how our autograder works 1 #include 2 #include 3 4 int main(void) { 5 6 7 8 9 10 11 12445 14 15) Run char condStr[50]; int userval; scanf("%d", &userval); strcpy(condStr, /* Your solution goes here */); printf("%d is %s.\n", userval, condStr); return 0; DID
CHALLENGE 3.16.2: Conditional expression: Print negative or positive. ACTIVITY Create a conditional expression that evaluates to string "negative" if userval is less than 0, and "non-negative" otherwise. Ex If userval is-9, output is: -9 is negative. Replace the code comment/* Your solution goes here */ with your solution. The rest of the code, including the parentheses and semicolon, cannot be edited. Learn how our autograder works 1 #include 2 #include 3 4 int main(void) { 5 6 7 8 9 10 11 12445 14 15) Run char condStr[50]; int userval; scanf("%d", &userval); strcpy(condStr, /* Your solution goes here */); printf("%d is %s.\n", userval, condStr); return 0; DID
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Question
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C

Here is the partially completed code:
```c
#include <stdio.h>
#include <string.h>
int main(void) {
char condStr[50];
int userVal;
scanf("%d", &userVal);
strcpy(condStr, /* Your solution goes here */);
printf("%d is %s.\n", userVal, condStr);
return 0;
}
```
Click the "Run" button to check your solution.
##### Expected Output for Input -9
```
-9 is negative.
```
You can see the autograder status and if your solution passes all tests. This ensures your implementation is correct.
---
This challenge helps you to:
- Learn to use conditional expressions in C.
- Practice handling user input and string operations.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3e035166-c990-4dd0-a7c5-b2c139b07c7d%2F5484a72a-89ca-4773-8141-aab48ce64045%2Fgei49d9_processed.png&w=3840&q=75)
Transcribed Image Text:### Section 3.16: Conditional Expressions in C Programming
#### Conditional Expressions: Print Negative or Positive
##### Challenge Activity 3.16.2
Create a conditional expression that evaluates to the string "negative" if `userVal` is less than 0, and "non-negative" otherwise. For example, if `userVal` is -9, the output should be:
```
-9 is negative.
```
Replace the code comment `/* Your solution goes here */` with your solution. The rest of the code, including the parentheses and semicolon, cannot be edited.
[Learn how our autograder works](#)
Here is the partially completed code:
```c
#include <stdio.h>
#include <string.h>
int main(void) {
char condStr[50];
int userVal;
scanf("%d", &userVal);
strcpy(condStr, /* Your solution goes here */);
printf("%d is %s.\n", userVal, condStr);
return 0;
}
```
Click the "Run" button to check your solution.
##### Expected Output for Input -9
```
-9 is negative.
```
You can see the autograder status and if your solution passes all tests. This ensures your implementation is correct.
---
This challenge helps you to:
- Learn to use conditional expressions in C.
- Practice handling user input and string operations.
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