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CHALLENGE 3.16.2: Conditional expression: Print negative or positive. ACTIVITY Create a conditional expression that evaluates to string "negative" if userval is less than 0, and "non-negative" otherwise. Ex If userval is-9, output is: -9 is negative. Replace the code comment/* Your solution goes here */ with your solution. The rest of the code, including the parentheses and semicolon, cannot be edited. Learn how our autograder works 1 #include 2 #include 3 4 int main(void) { 5 6 7 8 9 10 11 12445 14 15) Run char condStr[50]; int userval; scanf("%d", &userval); strcpy(condStr, /* Your solution goes here */); printf("%d is %s.\n", userval, condStr); return 0; DID

CHALLENGE 3.16.2: Conditional expression: Print negative or positive. ACTIVITY Create a conditional expression that evaluates to string "negative" if userval is less than 0, and "non-negative" otherwise. Ex If userval is-9, output is: -9 is negative. Replace the code comment/* Your solution goes here */ with your solution. The rest of the code, including the parentheses and semicolon, cannot be edited. Learn how our autograder works 1 #include 2 #include 3 4 int main(void) { 5 6 7 8 9 10 11 12445 14 15) Run char condStr[50]; int userval; scanf("%d", &userval); strcpy(condStr, /* Your solution goes here */); printf("%d is %s.\n", userval, condStr); return 0; DID

Database System Concepts
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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C Programming please, need help.

### Section 3.16: Conditional Expressions in C Programming #### Conditional Expressions: Print Negative or Positive ##### Challenge Activity 3.16.2 Create a conditional expression that evaluates to the string "negative" if `userVal` is less than 0, and "non-negative" otherwise. For example, if `userVal` is -9, the output should be: ``` -9 is negative. ``` Replace the code comment `/* Your solution goes here */` with your solution. The rest of the code, including the parentheses and semicolon, cannot be edited. [Learn how our autograder works](#) Here is the partially completed code: ```c #include <stdio.h> #include <string.h> int main(void) { char condStr[50]; int userVal; scanf("%d", &userVal); strcpy(condStr, /* Your solution goes here */); printf("%d is %s.\n", userVal, condStr); return 0; } ``` Click the "Run" button to check your solution. ##### Expected Output for Input -9 ``` -9 is negative. ``` You can see the autograder status and if your solution passes all tests. This ensures your implementation is correct. --- This challenge helps you to: - Learn to use conditional expressions in C. - Practice handling user input and string operations.
Transcribed Image Text:### Section 3.16: Conditional Expressions in C Programming #### Conditional Expressions: Print Negative or Positive ##### Challenge Activity 3.16.2 Create a conditional expression that evaluates to the string "negative" if `userVal` is less than 0, and "non-negative" otherwise. For example, if `userVal` is -9, the output should be: ``` -9 is negative. ``` Replace the code comment `/* Your solution goes here */` with your solution. The rest of the code, including the parentheses and semicolon, cannot be edited. [Learn how our autograder works](#) Here is the partially completed code: ```c #include <stdio.h> #include <string.h> int main(void) { char condStr[50]; int userVal; scanf("%d", &userVal); strcpy(condStr, /* Your solution goes here */); printf("%d is %s.\n", userVal, condStr); return 0; } ``` Click the "Run" button to check your solution. ##### Expected Output for Input -9 ``` -9 is negative. ``` You can see the autograder status and if your solution passes all tests. This ensures your implementation is correct. --- This challenge helps you to: - Learn to use conditional expressions in C. - Practice handling user input and string operations.
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