CH4 + 2 O2 = CO2 + 2 H2OEnter whichever is greater: the number of grams of CO2 produced by 16.0 grams of methane, or the number of grams of CO2 produced by 16.0 L of oxygen.

Answered: CH4 + 2 O2 = CO2 + 2 H2O Enter…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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CH₄ + 2 O_{2 =}CO₂ + 2 H₂O

Enter whichever is greater: the number of grams of CO₂ produced by 16.0 grams of methane, or the number of grams of CO₂ produced by 16.0 L of oxygen.

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${CH}_{4} + 2 O_{2} = {CO}_{2} + 2 H_{2} O from the above equation, it is clear that 1 mole {CH}_{4} give 1 mole {CO}_{2} and 2 mole O_{2} give 1 mole {CO}_{2} . ∴ 16 g {CH}_{4} produce 44 g {CO}_{2} 2 mole oxygen = 2 \times 22.4 L ∴ 44.8 L O_{2} give 44 g {CO}_{2} 16 L O_{2} give = (\frac{44}{44.8} \times 16) g {CO}_{2} = 15.71 g {CO}_{2} Hence, 16 g {CH}_{4} produce more no of grams of {CO}_{2} compare to 16 L of O_{2}$

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