Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Kk.160.

Transcribed Image Text:### Chemical Reaction and Mechanism Analysis
**Reactants:**
1. Two methyl groups (CH3) attached to a six-membered cyclohexane ring.
2. A bromine atom (Br) attached to the cyclohexane ring.
**Reagents:**
1. Methoxide ion (-OCH₃) in a methanol (CH₃OH) solution.
**Mechanism:**
In this reaction, the methoxide ion functions as a nucleophile. The bromine atom attached to the cyclohexane ring is a leaving group, which will be replaced by the methoxide ion through an SN2 (bimolecular nucleophilic substitution) mechanism.
### Steps in the Mechanism:
1. The bromine atom (Br) attached to the cyclohexane ring is a good leaving group.
2. Methoxide ion (-OCH₃), being a strong nucleophile, will attack the carbon atom that is bonded to the bromine atom.
3. The attack of the methoxide ion causes the bromine to leave, effectively replacing the bromine atom with an -OCH₃ group attached to the ring.
### Expected Product:
- The final product will have the original cyclohexane ring structure with the bromine replaced by a methoxy group (-OCH₃).
- The methyl groups (CH₃) attached to the cyclohexane ring remain unchanged.
### Summary:
This reaction involves the replacement of a bromine atom with a methoxy group through a nucleophilic substitution reaction facilitated by methoxide ion in methanol.
This is a simplified explanation ideal for educational purposes, especially for students learning about substitution reactions and reaction mechanisms in organic chemistry.
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