Ch. 7-2 pg. 236 pp#1-2: Average Atomic Mass Find avg at mass Ga if 60.00% has mass 68.926 amu & 40.00% a mass of 70.925 amu. Ans.: = 69.73 amu 68.926 0.6 oll+x-(1-0.6011)= 69.73 amu 2. Find avg O, if 99.76% = 15.99amu, 0.038% = 17.00 amu, & 0.20% of it is18.00 amu. Ans.: = 15,99 %3D 44amu Ch. 7.2 p. 253, 42. Find avg at mass Ag if 51.35% is 106.9050 amu and the rest is 108.9045 amu. Ans. = 107.88 amu.

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**Chapter 7 WS #2**

**Ch. 7-2 pg. 236 pp#1-2: Average Atomic Mass**

1. Find the average atomic mass of Ga if 60.00% has a mass of 68.926 amu & 40.00% a mass of 70.925 amu.  
   Calculation:  
   \(68.926 \times 0.60 + x \times (1 - 0.60) = 69.73 \text{ amu}\)  
   **Answer:** 69.73 amu

2. Find the average atomic mass of \(O_2\) if 99.76% = 15.99 amu, 0.038% = 17.00 amu, & 0.20% of it is 18.00 amu.  
   **Answer:** 15.99 amu

**Ch. 7.2 p. 253**

42. Find the average atomic mass of Ag if 51.35% is 106.9050 amu and the rest is 108.9045 amu.  
   **Answer:** 107.88 amu

---

**CH. 7-2 pg. 239 pp#1 Molar Mass**

Find the molar mass for each of the following compounds:

- CsI: 259.8 g/mol
- \(C_{12}H_{22}O_{11}\): 342.3 g/mol
- \(I_2\): 253.8 g/mol
- \(Mg_3(PO_4)_2\): 262.9 g/mol

**CH. 7-2 pg. 239 pp#2**

Write the formula and then find the molar mass for the following:

- Cerium hexaboride \(CeB_6\): 204.98 g/mol
- Aluminum sulfate \(Al_2(SO_4)_3\): 342.17 g/mol
- Iron (III) hydroxide \(Fe(OH)_3\): 106.87 g/mol
- Tin(II) chloride \(SnCl_2\): 189.6 g/mol
- Tetraphosphorus decoxide \(P_4O_{10}\): 141.94 g/mol

**Ch. 7-2 SR pg. 240 pp#11
Transcribed Image Text:**Chapter 7 WS #2** **Ch. 7-2 pg. 236 pp#1-2: Average Atomic Mass** 1. Find the average atomic mass of Ga if 60.00% has a mass of 68.926 amu & 40.00% a mass of 70.925 amu. Calculation: \(68.926 \times 0.60 + x \times (1 - 0.60) = 69.73 \text{ amu}\) **Answer:** 69.73 amu 2. Find the average atomic mass of \(O_2\) if 99.76% = 15.99 amu, 0.038% = 17.00 amu, & 0.20% of it is 18.00 amu. **Answer:** 15.99 amu **Ch. 7.2 p. 253** 42. Find the average atomic mass of Ag if 51.35% is 106.9050 amu and the rest is 108.9045 amu. **Answer:** 107.88 amu --- **CH. 7-2 pg. 239 pp#1 Molar Mass** Find the molar mass for each of the following compounds: - CsI: 259.8 g/mol - \(C_{12}H_{22}O_{11}\): 342.3 g/mol - \(I_2\): 253.8 g/mol - \(Mg_3(PO_4)_2\): 262.9 g/mol **CH. 7-2 pg. 239 pp#2** Write the formula and then find the molar mass for the following: - Cerium hexaboride \(CeB_6\): 204.98 g/mol - Aluminum sulfate \(Al_2(SO_4)_3\): 342.17 g/mol - Iron (III) hydroxide \(Fe(OH)_3\): 106.87 g/mol - Tin(II) chloride \(SnCl_2\): 189.6 g/mol - Tetraphosphorus decoxide \(P_4O_{10}\): 141.94 g/mol **Ch. 7-2 SR pg. 240 pp#11
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